I have a for loop as shown below. I need the whole output of the loop added into an array or variable.
for i in $ip
do
curl -s $i:9200
done
Any idea how I can achieve that?
Add a comment
|
3 Answers
You can use it like this:
# declare an array
declare -a arr=()
for i in $ip
do
# append each curl output into our array
arr+=( "$(curl -s $i:9200)" )
done
# check array content
declare -p arr
It is important to use quotes around curl comment to avoid splitting words of curl command's output into multiple array entries. With quotes all of the curl output will become a single entry in the array.
4 Comments
codeforester
Great one @anubhava. I think it would be nice if you could explain why the curl command needs to be inside double quotes.
zozo6015
what I need is to add the output of that curl command to the array, Not the command itself.
anubhava
@zozo6015: Using
$(...) i.e command substitution we are adding output of curl command not the command itself.anubhava
Thanks @codeforester. I've added some explanation in my answer.
You can use +=
declare -a output
for i in $ip
do
output+=("$(curl -s $i:9200)")
done
2 Comments
zozo6015
I get
-bash: syntax error near unexpected token ('`
Richard Hamilton
Yep. Just tested it out, and apparently you can't have a space before
+=. Well, you learn something new every dayYou can capture the output of any command, including a compound command, by enclosing it in $(). Using that technique, you can capture the output of your for loop in a variable like so:
results=$(
for i in $ip
do
curl -s $i:9200
done
)
In principle, capturing into an array can be done in similar fashion, but handling element delimiters appropriately could prove difficult.
