Print values of arrays inside for loop using bash

Question

I am trying to print the $a and $BIT values.

But I'm receiving the value of $BIT but not $a.

Please find the code as follows,

echo "Content-type: text/html"
echo ""
echo "<html><head><META HTTP-EQUIV='refresh' CONTENT="1"></head>"
VAL[0] =1;
VAL[1] =0;
VAL[2] =1;

for CNT in $(seq 32)
do
    BIT = ${VAL[$CNT]};
    a = $(($CNT-1));

echo "<p>$a,$BIT</p>";
done

Please help me on this.

Thanks in advance.

I assume in your original you don't have spaces around the equals (=)? I ran your script and it ran fine, although the for CNT... loop starts with CNT value of 1, but you probably intend 0. It does otherwise show the defined values of both $a and $BIT. — lurker
– lurker, Commented Feb 26, 2015 at 12:07
as @lurker says, I hope you equal signs are good. I don't see any problem otherwise. To avoid computing the $a, you could try for CNT in $( seq 0 31) and your problems will go away (as @lurker says, you will have the proper array entry and no need to compute $a, just use $CNT) — tgo
– tgo, Commented Feb 26, 2015 at 12:17

Vasanth · Accepted Answer · 2015-02-27 07:30:49Z

1

I have changed my code like below. My issue got resloved.

    echo "Content-type: text/html"
    echo ""
    echo "<html><head><META HTTP-EQUIV='refresh' CONTENT="1"></head>"
    VAL[0]=1;
    VAL[1]=0;
    VAL[2]=1;

    for CNT in $(seq 0 31)
    do
        a=$CNT;

    echo "<p>$a,$BIT</p>";
    done

edited Feb 27, 2015 at 7:30

answered Feb 26, 2015 at 12:25

Vasanth

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1 Comment

David W. Over a year ago

I can't see how this resolved your issue. The $BIT variable isn't set anywhere, and VAL[0] =1 isn't valid Bash code due to the space.

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