Javascript replace characters of an element in an array

Question

I am trying to replace characters within an array of strings.

so far i have this:

stuff= ["uyuuyu", "76gyuhj***", "uiyghj", "56tyg", "juijjujh***"];

for(var i = 0; i < stuff.length; i++)
{
    if(stuff[i].indexOf('***') != -1)
    {
        // this is where i guess the replacing would go
    }
}

I figured out that i can use this code to display with element in the array has the characters *** now want to replace the *** characters with a number so that it outputs a new array ( the same array but modified) that looks like :

  stuff= ["uyuuyu", "76gyuhj0", "uiyghj", "56tyg", "juijjujh0"];

I can't seem to figure out how to replace the characters within that array without effecting the rest of the array

How is the number determined (is it always 0)? What to do with more than 3 asterisks? — raina77ow
– raina77ow, Commented Sep 21, 2016 at 19:05
assume the number will always be 0 and there will always be 3 asterisks. i should update that into the post — sourlemonaid
– sourlemonaid, Commented Sep 21, 2016 at 19:07
@JennyO'Reilly i just mean without rearranging the elements. so it always stays in the same position. the only way i thought of doing it was to remove that part of the array and then use replace on the string and then push it back in somehow? or splice. i hope that makes sense — sourlemonaid
– sourlemonaid, Commented Sep 21, 2016 at 19:08

user94559 · Accepted Answer · 2016-09-21 19:05:43Z

15

Also consider .replace(/\*\*\*/g, '0') if you want to replace multiple occurrences of ***. (The below code only replaces the first occurrence in each string.)

stuff= ["uyuuyu", "76gyuhj***", "uiyghj", "56tyg", "juijjujh***"];

for(var i = 0; i < stuff.length; i++)
{
    stuff[i] = stuff[i].replace('***', '0');
}

console.log(stuff);

Note that there's no need to check indexOf. If the substring isn't present, the replace just doesn't change anything, so you can just apply the replace to every string.

answered Sep 21, 2016 at 19:05

user94559

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1 Comment

Patrik Krehák Over a year ago

Or use regex and it will replace every *** with 0 - stuff[i] = stuff[i].replace(/(\*\*\*)/g, '0');

Machavity · Accepted Answer · 2024-08-18 12:39:38Z

10

you can use javascript map as below

 var newStuff = stuff.map(function(item,index){
  return item.replace('***','0')

});

console.log(newStuff) //["uyuuyu", "76gyuhj0", "uiyghj", "56tyg", "juijjujh0"]

es2015 (es6) with arrow function

var newStuff = stuff.map(item => item.replace('***','0'));

edited Aug 18, 2024 at 12:39

Machavity♦

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answered Sep 21, 2016 at 19:08

Shushanth Pallegar

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1 Comment

sourlemonaid Over a year ago

I really like this way! thank you. going to accept a different answer because the name of the array didn't change. which is a little better for me in what i'm trying to do. but i will keep a note of your answer too. learned a lot from it

Yatendrasinh Joddha · Accepted Answer · 2016-09-21 19:09:14Z

0

var stuff= ["uyuuyu", "76gyuhj***", "uiyghj", "56tyg", "juijjujh***"];

for(var i = 0; i < stuff.length; i++)
{
    if(stuff[i].indexOf('***') != -1)
{
        stuff[i] = stuff[i].replace('***','0')
    // this is where i guess the replacing would go
}
console.log(stuff[i]);
}

answered Sep 21, 2016 at 19:09

Yatendrasinh Joddha

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Comments

Fattie · Accepted Answer · 2024-08-18 14:01:03Z

0

it's just

 stuff = stuff.map(item => item.replace('***','0'))

if you want to "keep it as the same variable" as asked by the OP in a comment.

Also importantly ..

Tip 1:

You almost always want "replaceAll", not "replace"

= stuff.map(t => t.replaceAll('***','0'))

Tip 2 - crash issue:

Very annoyingly it will fail and crash if the item is not a string, such as a number. So you really always need

= stuff.map(t => t.toString.replaceAll('***','0'))

Example:

Array of items, convert to csv -like string

 const simple_csv = someArray
        .map(t => t.toString().replaceAll(',', ';') )
        .join(",")

answered Aug 18, 2024 at 14:01

Fattie

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Comments

ninjawarrior · Accepted Answer · 2016-09-21 19:08:55Z

-1

This is simple. Use replace function to modify the strings

stuff= ["uyuuyu", "76gyuhj***", "uiyghj", "56tyg", "juijjujh***"];

for(var i = 0; i < stuff.length; i++)
{
        stuff[i] = stuff[i].replace('***', '');
}

edited Sep 21, 2016 at 19:08

answered Sep 21, 2016 at 19:06

ninjawarrior

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