I need to filter an array1, with each element in my array 2. Both arrays can have a random number of elements.
array1 = [1,2,3,4,5];
array2 = [1,3,5];
filteredArray = [];
array2.forEach(function(x){
filteredArray = array1.filter(function(y){
return y !== x;
});
});
return filteredArray;
//should return -> [2,4]
// returns [1,2,3,4]
How can I filter an array with all elements in another array?
use arrays indexOf method
var array1 = [1,2,3,4,5];
var array2 = [1,3,5];
var filteredArray = array1.filter(function(x) {
return array2.indexOf(x) < 0;
});
or, for sexy people, use !~ with indexOf
var array1 = [1,2,3,4,5];
var array2 = [1,3,5];
var filteredArray = array1.filter(function(x) {
return !~array2.indexOf(x);
});
array1 = [1, 2, 3, 4, 5];
array2 = [1, 3, 5];
filteredArray = [];
filteredArray = array1.filter(function (y) {
return array2.indexOf(y) < 0;
});
console.log(filteredArray);A much simpler way would be:
var filteredArray = array1.filter(function(item) {
return !(array2.indexOf(item) >= 0);
});
return !(array2.indexOf(item) >= 0); that should do the trick.!~!( ... >= 0) just ... < 0!(a.indexOf(b) >= 0) is 100% identical to a.indexOf(b) < 0 ... or, more simply ... !(a >= 0) === a < 0You can use indexOf() to check if the array2 item is in array1 then only add it to filteredArray if it is:
array1 = [1,2,3,4,5];
array2 = [1,3,5];
filteredArray = [];
array2.forEach(function(x){
if (array1.indexOf(array2[x] > -1) {
filteredArray.push(array2[x]);
}
});
return filteredArray;
In ES6, you could use Set for it.
var array1 = [1, 2, 3, 4, 5],
array2 = [1, 3, 5],
filteredArray = array1.filter((set => a => !set.has(a))(new Set(array2)));
console.log(filteredArray);
filteredArray = array1.filter(function(set,a) {return !set.has(a)}.bind(null,new Set(array2)));..?
new Set(...) as this args.All indexOf no play makes me a dull boy...
var array1 = [1,2,3,4,5],
array2 = [1,3,5],
filtered = array1.filter(e => !array2.includes(e));
console.log(filtered);