JavaScript Parsing array and getting the unique value

Question

I have the following array:

    array-1:

        Array[11]
        0:"265"
        1:"text-success"
        2:"51"
        3:"text-warning"
        4:"16"
        5:"text-warning"
        6:"35"
        7:"text-warning"
        8:"38"
        9:"text-warning"
        10:"106"

    array-2:
        Array[11]
        0:"265"
        1:"text-success"
        2:"51"
        3:"text-warning"
        4:"16"
        5:"text-warning"
        6:"35"
        7:"text-success"
        8:"38"
        9:"text-warning"
        10:"106"

   array-3:
        Array[11]
        0:"265"
        1:"muted"
        2:"51"
        3:"text-warning"
        4:"16"
        5:"text-warning"
        6:"35"
        7:"text-success"
        8:"38"
        9:"text-warning"
        10:"106"

    array-4:
        Array[11]
        0:"265"
        1:"text-warning"
        2:"51"
        3:"text-warning"
        4:"16"
        5:"muted"
        6:"35"
        7:"text-warning"
        8:"38"
        9:"text-warning"
        10:"106"

1st one will return FALSE because both exist "text-success"-twice AND "muted"-once

2nd one will return TRUE because it exist ONCE "text-success"

3rd one will return FALSE because both exist "text-success" AND "muted"

4th one will return TRUE because it exist ONCE "muted"

I need to parse the array and get the result:

array-1:

    Array[11]
        0:"265"
        1:"text-success"
        2:"51"

array-2: Null

array-3: Null

array-4:

    Array[11]
        0:"265"
        1:"muted"
        2:"16"

so far I have this:

function singles( array) {
    for( var index = 0, single = []; index < array.length; index++ ) { 
        if(array[index] == "text-success" || array[index] == "muted") {
            single.push(array[index]);
        }
    }
    return single;
};

Please help anyone?

What problem are you actually trying to solve? This screams "ugly workaround-hack" to me. — Tom Lord
– Tom Lord, Commented Jul 25, 2016 at 13:16

nnnnnn · Accepted Answer · 2016-07-26 07:43:47Z

It's not clear whether you have an object that contains multiple arrays, or just a standard one-dimensional array for which you've given several possible examples, but assuming the latter I think this is what you're looking for:

function singles(array) {
  var foundIndex = -1;
      
  for(var index = 0; index < array.length; index++) {
    if(array[index] === "text-success" || array[index] === "muted") {
      if (foundIndex != -1) {
        // we've found two, so...
        return null;
      }
      foundIndex = index;
    }
  }
  if (foundIndex != -1) {
    return [ array[0], array[foundIndex], array[foundIndex+1] ];
  }
  return "Some default value for when it wasn't found at all";
}

console.log(singles(["532","text-warning","51","text-warning","16","muted","35","text-warning","38","text-warning","106"]));
console.log(singles(["533","text-warning","51","text-warning","16","muted","35","text-success","38","text-warning","106"]));

This loops through the input array. The first time "text-success" or "muted" is found its index is stored in foundIndex.

If "text-success" or "muted" is found a second time we immediately return null.

If we get to the end of the loop then we know we found "text-success" or "muted" either once or not at all. If it was found once we return an array of three elements included the first item in the input array, the value of "text-success" or "muted", and then the item that immediately followed that text in the array.

(Note: in your example output from Array 1 you returned the value after the matched text, but in your example output from Array 4 you returned the value before the matched text. I don't know which one you really want, but you can easily modify my function to do one or the other.)

You didn't say what you wanted to return if "text-success" or "muted" wasn't present in the array, so I've just returned a place-holder string.

ultimatik · Accepted Answer · 2016-07-25 13:09:37Z

0

If you want to test if it exists "text-success" or "muted" once in the array, use this function, it will return a boolean:

function singles(array) {
    var single = false;
    for (var i = 0; i < array.length; i++) {
        if (array[i] === "text-success" || array[i] === "muted") {
            if (single) {
                return false;
            }
            single = true;
        }
    }
    return single;
}

If you want to return the unique value among "text-success" or "muted", use the following function. It will return the unique value, or null otherwise:

function singles(array) {
    var single = null;
    for (var i = 0; i < array.length; i++) {
        if (array[i] === "text-success" || array[i] === "muted") {
            if (single) {
                return null;
            }
            single = array[i];
        }
    }
    return single;
}

If you need the code of the corresponding value, use this:

function singles(array) {
    var single = null;
    for (var i = 1; i < array.length; i += 2) {
        if (array[i] === "text-success" || array[i] === "muted") {
            if (single) {
                return null;
            }
            single = array[i - 1];
        }
    }
    return single;
}

edited Jul 25, 2016 at 13:09

answered Jul 25, 2016 at 12:41

ultimatik

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4 Comments

Malarivtan Over a year ago

Array[11] 0:"265" 1:"text-success" 2:"51"

Malarivtan Over a year ago

Do I need to group them

ultimatik Over a year ago

@TanvirAlam I added the code to my answer to get the identifier of the unique value.

ultimatik Over a year ago

@TanvirAlam Oops sorry, replaced i *= 2 by i += 2

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