Javascript Object array parsing issue

Question

I have the following object in Javascript:

Array[11]
0:"532"
1:"text-warning"
2:"51"
3:"text-warning"
4:"16"
5:"muted"
6:"35"
7:"text-warning"
8:"38"
9:"text-warning"
10:"106"

Array[11]
0:"533"
1:"text-warning"
2:"51"
3:"text-warning"
4:"16"
5:"muted"
6:"35"
7:"text-success"
8:"38"
9:"text-warning"
10:"106"

Array[11]
0:"534"
1:"text-warning"
2:"51"
3:"text-warning"
4:"16"
5:"text-warning"
6:"35"
7:"text-success"
8:"38"
9:"text-warning"
10:"106"

I would like to parse it and find if two value exist only once within this array.

Example: "text-success" OR "muted" if EXIST ONCE return the array

if it EXIST twice return null

if TRUE return the corresponding id

In the above example:

1st Array: is TRUE

Array[11]
0:"532"
1:"muted"
2:"35"

2nd one is FALSE because its exist twice

3rd one: is also TRUE

Array[11]
0:"534"
1:"text-success"
2:"38"

I have been trying this past few days was not successful

I have the following JQUERY: but it only gets the Unique value but discard the others:

I need the first id and the corresponding id as well:

Array[11]
0:"534" -> main id (needed)
1:"text-success"
2:"38" ->  company id (needed)



function singles( array) {
    for( var index = 0, single = []; index < array.length; index++ ) { 

        if(array[index] == "text-success" || array[index] == "muted") {
            single.push(array[index]);
        }
    }
    return single;
};

The result or the output which is required:

  Array[11]
    0:"532",
    1:"muted",
    2:"35",

The first value is the Main ID, the 2nd value is the UNIQUE and the 3rd value is the corresponding ID for the unique value.

Where is your jQuery?

choz
– choz

2016-07-26 06:51:17 +00:00
Commented Jul 26, 2016 at 6:51 — choz
– choz, Commented Jul 26, 2016 at 6:51
please add the object/array as text literal.

Nina Scholz
– Nina Scholz

2016-07-26 06:51:17 +00:00
Commented Jul 26, 2016 at 6:51 — Nina Scholz
– Nina Scholz, Commented Jul 26, 2016 at 6:51
@choz it is there, please have a look

Malarivtan
– Malarivtan

2016-07-26 06:52:17 +00:00
Commented Jul 26, 2016 at 6:52 — Malarivtan
– Malarivtan, Commented Jul 26, 2016 at 6:52
@NinaScholz what do u mean?

Malarivtan
– Malarivtan

2016-07-26 06:52:30 +00:00
Commented Jul 26, 2016 at 6:52 — Malarivtan
– Malarivtan, Commented Jul 26, 2016 at 6:52
something like var o = { a: "foo", b: 42, c: {} };.

Nina Scholz
– Nina Scholz

2016-07-26 06:54:14 +00:00
Commented Jul 26, 2016 at 6:54 — Nina Scholz
– Nina Scholz, Commented Jul 26, 2016 at 6:54

kollein · Accepted Answer · 2016-07-26 08:29:58Z

1

You can solve:

transform Object to Array

Check duplicated element then pass

unique element push into new array

var obj = {
0:"532",
1:"text-warning",
2:"51",
3:"text-warning",
4:"16",
5:"muted",
6:"35",
7:"text-warning",
8:"38",
9:"text-warning",
10:"106"
};


function restUnique(obj){
 var mix = [];
 var output= [];
 Object.keys(obj).forEach(function(key) {

    mix[key]=obj[key];

 });

 for(var i in mix){
  fb=mix.indexOf(mix[i]);
  fa=mix.lastIndexOf(mix[i]);
  if(fb===fa){output.push(mix[i]);}
 }
return output;
}
// usage example:
restUnique(obj); // output : 532,51,16,muted,35,38,106

edited Jul 26, 2016 at 8:29

answered Jul 26, 2016 at 8:23

kollein

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