I've this script: an array of array, and a loop. Inside the loop, how can I print the key (foo) and the value (bar)???
#!/bin/bash
declare -A combo=()
combo+=(['foo']='bar')
combo+=(['hello']='world')
for window in ${combo[@]};
do
echo ???
echo ???
done
exit
expected output:
key: foo value: bar
key: hello value:world
I'll read this bash manual asap!!
Your script is almost correct. As is v.coder's answer.
You need to declare your array as an associative one before you append items to it with string keys.
declare -A combo
Then you need to iterate over the keys of the array (${!combo[@]}") instead of the values (${combo[@]}").
Then the rest of v.coder's answer works just fine.
#!/bin/bash
declare -A combo
combo+=(['foo']='bar')
combo+=(['hello']='world')
for window in "${!combo[@]}"
do
echo "${window}" # foo
echo "${combo[${window}]}" # bar
done
combowill have one array element that isbarworlddeclare -A. If they did this would do what they expected. So a more constructive version of your comment here (and on the posted answer) would likely have been more useful.