JavaScript function to check if only has digits or decimals in string

Question

I am trying to check to see if my string only have numbers or decimals in it using JavaScript.

If it has only numbers or decimals in the string then it should pass else it want to display a alert saying there is a error.

I have tried using the following code but it doesn't alert anything..

Am I doing something wrong?

var myString = "abc"; 

        if (myString.matches("[0-9].") && myString.length() > 2) 
        {
            alert("Pass");
        }
        else
        {
            alert("Error");
        }

length is not a function... so that's why nothing was happening. mystring.length > 2 — Koenyn
– Koenyn, Commented Nov 8, 2012 at 7:03

Damask · Accepted Answer · 2012-11-08 07:09:23Z

1

Let's simplify :-)

 if (/^[\d\.]{3,}$/.test(myString)) {
    alert("Pass");
 } else {
    alert("Error");
 }

edited Nov 8, 2012 at 7:09

answered Nov 8, 2012 at 7:03

Damask

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3 Comments

elclanrs Over a year ago

Lol just noticed that I put d{2,} too, and changed it as well.

Aaron Over a year ago

If I make myString = "12.3" it displays Error where decimals should be allowed as well as 0-9

Damask Over a year ago

Note: there may be a problems, cause text 1..2 will match too. Use something more complex like: \d+(\.\d+)? and then make check your string length

Pragnesh Chauhan · Accepted Answer · 2012-11-08 07:22:02Z

1

use ^\d*[0-9](\.\d*[0-9])?$

DEMO

if (myString.match(/^\d*[0-9](\.\d*[0-9])?$/) && myString.length > 2) {
        alert("Pass");
    } else {
        alert("Error");
    }

edited Nov 8, 2012 at 7:22

answered Nov 8, 2012 at 7:01

Pragnesh Chauhan

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Comments

user1726343 · Accepted Answer · 2012-11-08 07:00:33Z

0

Try:

/^\d+$/.test(myString)

Returns a boolean instead of an array or null, which is what match does. Altogether:

if (/^\d{2,}$/.test(myString)){ 
...
}else{
...
}

answered Nov 8, 2012 at 7:00

user1726343

Comments

elclanrs · Accepted Answer · 2012-11-08 07:03:05Z

0

You could put it all together like this:

alert( /^\d{3,}$/.test( myString ) ? 'Pass' : 'Error' )

answered Nov 8, 2012 at 7:03

elclanrs

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Comments

syarul · Accepted Answer · 2012-11-08 07:14:44Z

0

Your code is wrong myString.length() is a function not actually a length of myString

var myString = "abc"; 

    if (myString.match(/[0-9]/, "g") && myString.length > 2) 
    {
        alert("Pass");
    }
    else
    {
        alert("Error");
    }

answered Nov 8, 2012 at 7:14

syarul

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