How can I get this code to return just the one false alert, since it contains a number when I'm checking that what's in the string "name" should all be lowercase alphas?
var name = "Bob1";
var i = 0;
var name = name.toLowerCase()
for(i=0; i<name.length; i++){
if((name.charCodeAt(i)>96) && (name.charCodeAt(i)<123)) {
alert("true");
} else {alert("false");}
}
I would go with regex for this one:
if(name.match(/\d/)) {
// this contains at least one number
}
else {
// this doesn't contain any numbers
}
Since people will notice the upvoted answer, I will reference an even better solution for your case. This is mentioned by Ray Toal (credits / upvotes to him for this case):
Since you only want to allow undercase alpha's for your name, you can handle this directly too (this will cover issues with hyphens et cetera too):
if(name.match(/^[a-z]+$/)) {
// this contains only undercase alpha's
}
else {
// this contains at least one character that's not allowed
}
If you want to alert that all characters are in the range a through z you can use a regex that says that directly
alert(/^[a-z]+$/.test(name1.toLowerCase()))
You can also invert the condition and say that you want the value false if the string contains at least one non-letter:
alert(!(/[^a-z]/.test(name1.toLowerCase())))
add a break statement so new code would look like this inside the if statement
if((name.charCodeAt(i)>96) && (name.charCodeAt(i)<123))
{alert("true");
break;
}else
... basically it just exits the for loop (same command works in while loops as well)
break; is command your looking forput a break; inside the else , so that it gets out of the loop after alerting false for the first time
