How convert int's to byte array with two fixed values

Question

I'm sending five bytes to an Arduino:

byte[] { 0xF1, byte1, byte2, byte3, 0x33 }

The values of byte1, byte2 and byte3 are dynamic. The first and last bytes are always the same.

Byte values are from 0 to 255.

How can I simply convert ints to bytes and put them into my byte array?

syned · Accepted Answer · 2012-09-06 14:02:45Z

1

To get array of bytes from int use:

    byte[] intAsArrayOfBytes = BitConverter.GetBytes(yourInt);

then you can copy values to your array

   byte[] { 0xF1, intAsArrayOfBytes[0], intAsArrayOfBytes[1], intAsArrayOfBytes[3], 0x33 }

or if you need just convert int type into byte type and you know that variable between 0..255 use:

   byte byte1 = (byte) int1;
   byte byte2 = (byte) int2;
   byte byte3 = (byte) int3;

answered Sep 6, 2012 at 14:02

syned

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Comments

Paolo Moretti · Accepted Answer · 2012-09-06 14:07:51Z

0

If you are sure that your values won't exceed the byte range [0, 255], you can simply cast them:

byte[] b = { 0xF1, (byte)byte1, (byte)byte2, (byte)byte3, 0x33 }

In alternative you can use Convert.ToByte, which throws an OverflowException if values are less than 0 or greater than 255.

answered Sep 6, 2012 at 14:07

Paolo Moretti

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akton · Accepted Answer · 2012-09-06 13:59:06Z

0

Assuming the ints are between 0 and 255, use Convert.ToByte(). For example:

int byte1;
int byte2;
int byte3;
byte[] bytes = new byte[]{ 0xF1, Convert.ToByte(byte1), 
    Convert.ToByte(byte2), Convert.ToByte(byte3), 0x33 };

answered Sep 6, 2012 at 13:59

akton

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