Converting BYTE array to INT

Question

I have this kind of code

static void Main(string[] args)
{
     byte[] array = new byte[2] { 0x00, 0x1f };
     Console.WriteLine(BitConverter.ToInt32(array, 0));
}

However it does not work. It throws an exception:

Destination array is not long enough to copy all the items in the collection. Check array index and length.

What is wrong?

p.s.w.g · Accepted Answer · 2016-07-31 14:13:44Z

23

As the name suggests, an Int32 is 32 bits, or 4 bytes, so if you want to convert a byte array to an Int32, it needs to have a length of at least 4, (or more precisely, it needs to have least 4 bytes after the start position).

If all you have is two bytes, maybe you meant to use ToInt16?

edited Jul 31, 2016 at 14:13

answered Feb 7, 2014 at 23:29

p.s.w.g

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JaredPar · Accepted Answer · 2014-02-07 23:30:47Z

13

An Int32 is composed of 4 bytes but the array only has 2. One way to work around this is to first convert to Int16 and then to Int32

Console.WriteLine((Int32)(BitConverter.ToInt16(array, 0)));

Note that in this specific usage converting to Int32 from Int16 doesn't change anything because the numbers print the same.

answered Feb 7, 2014 at 23:30

JaredPar

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2 Comments

Andrejovich Over a year ago

Just as writing the decimal number "10" as "0010" doesn't change anything else either: the additional zeroes are meaningless, and you're more or less doing the same when you convert an Int16 to an Int32.

computercarguy Over a year ago

FYI, Visual Studio 2022 using .Net 6 says the Int32 conversion is redundant.

Robert Hegner · Accepted Answer · 2020-05-05 19:09:01Z

8

This is an old question, but for .NET Core / .NET Standard > 2.1 there is new solution:

The System.Buffers.Binary.BinaryPrimitives class provides two static methods ReadInt32BigEndian and ReadInt32LittleEndian for this purpose.

Using this these methods has two advantages:

It lets you explicitly specify if your number is stored as little endian or big endian.
They accept a Span<T> which can be a performance advantage, depending on the scenario.

answered May 5, 2020 at 19:09

Robert Hegner

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Grant Winney · Accepted Answer · 2014-02-07 23:29:18Z

4

The documentation on BitConverter.ToInt32 says:

The ToInt32 method converts the bytes from index startIndex to startIndex + 3 to an Int32 value.

You need to specify at least 4 bytes, but you only have 2.

answered Feb 7, 2014 at 23:29

Grant Winney

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