Stewart calc7e 01_08

Copyright © Cengage Learning. All rights reserved.
1 Functions and Limits

Copyright © Cengage Learning. All rights reserved.
1.8 Continuity

33
Continuity
The limit of a function as x approaches a can often be
found simply by calculating the value of the function at a.
Functions with this property are called continuous at a.
We will see that the mathematical definition of continuity
corresponds closely with the meaning of the word
continuity in everyday language. (A continuous process is
one that takes place gradually, without interruption or
abrupt change.)

44
Continuity
Notice that Definition 1 implicitly requires three things if f is
continuous at a:
1. f(a) is defined (that is, a is in the domain of f)
2. exists
3.
The definition says that f is continuous at a if f(x)
approaches f(a) as x approaches a. Thus a continuous
function f has the property that a small change in x
produces only a small change in f(x).

55
Continuity
In fact, the change in f(x) can be kept as small as we
please by keeping the change in x sufficiently small.
If f is defined near a (in other words, f is defined on an open
interval containing a, except perhaps at a), we say that f is
discontinuous at a (or f has a discontinuity at a) if f is
not continuous at a.
Physical phenomena are usually continuous. For instance,
the displacement or velocity of a vehicle varies
continuously with time, as does a person’s height. But
discontinuities do occur in such situations as electric
currents.

66
Continuity
Geometrically, you can think of a function that is continuous
at every number in an interval as a function whose graph
has no break in it. The graph can be drawn without
removing your pen from the paper.

77
Example 1
Figure 2 shows the graph of a function f. At which numbers
is f discontinuous? Why?
Solution:
It looks as if there is a discontinuity when a = 1 because the
graph has a break there. The official reason that f is
discontinuous at 1 is that f(1) is not defined.
Figure 2

88
Example 1 – Solution
The graph also has a break when a = 3, but the reason for
the discontinuity is different. Here, f(3) is defined, but
limx→3 f(x) does not exist (because the left and right limits are
different). So f is discontinuous at 3.
What about a = 5? Here, f(5) is defined and limx→5 f(x) exists
(because the left and right limits are the same).
But
So f is discontinuous at 5.
cont’d

99
Example 2
Where are each of the following functions discontinuous?
Solution:
(a) Notice that f(2) is not defined, so f is discontinuous at 2.
Later we’ll see why f is continuous at all other numbers.

1010
(b) Here f(0) = 1 is defined but
does not exist. So f is discontinuous at 0.
(c) Here f(2) = 1 is defined and
= 3 exists.
cont’d

1111
But
so f is not continuous at 2.
(d) The greatest integer function f(x) = has
discontinuities at all of the integers because
does not exist if n is an integer.
cont’d

1212
Continuity
Figure 3 shows the graphs of the functions in Example 2.
Figure 3
Graphs of the functions in Example 2

1313
Continuity
Figure 3
Graphs of the functions in Example 2

1414
Continuity
In each case the graph can’t be drawn without lifting the
pen from the paper because a hole or break or jump occurs
in the graph.
The kind of discontinuity illustrated in parts (a) and (c) is
called removable because we could remove the
discontinuity by redefining f at just the single number 2.
[The function g(x) = x + 1 is continuous.]
The discontinuity in part (b) is called an infinite
discontinuity. The discontinuities in part (d) are called
jump discontinuities because the function “jumps” from
one value to another.

1616
Continuity
Instead of always using Definitions 1, 2, and 3 to verify the
continuity of a function, it is often convenient to use the
next theorem, which shows how to build up complicated
continuous functions from simple ones.

1717
Continuity
It follows from Theorem 4 and Definition 3 that if f and g are
continuous on an interval, then so are the functions
f + g, f – g, cf, fg, and (if g is never 0) f/g.
The following theorem was stated as the Direct Substitution
Property.

1818
Continuity
As an illustration of Theorem 5, observe that the volume of
a sphere varies continuously with its radius because the
formula V(r) = πr3
shows that V is a polynomial function of
r.
Likewise, if a ball is thrown vertically into the air with a
velocity of 50 ft/s, then the height of the ball in feet t
seconds later is given by the formula h = 50t – 16t2
.
Again this is a polynomial function, so the height is a
continuous function of the elapsed time.

1919
Continuity
It turns out that most of the familiar functions are
continuous at every number in their domains.
From the appearance of the graphs of the sine and cosine
functions, we would certainly guess that they are
continuous.
We know from the definitions of
sin θ and cos θ that the coordinates
of the point P in Figure 5 are
(cos θ, sin θ). As θ → 0, we see
that P approaches the point (1, 0)
and so cos θ → 1 and sin θ → 0. Figure 5

2020
Continuity
Thus
Since cos 0 = 1 and sin 0 = 0, the equations in assert
that the cosine and sine functions are continuous at 0.
The addition formulas for cosine and sine can then be used
to deduce that these functions are continuous everywhere.
It follows from part 5 of Theorem 4 that
is continuous except where cos x = 0.

2121
Continuity
This happens when x is an odd integer multiple of π/2, so
y = tan x has infinite discontinuities when
x = ±π/2, ±3π/2, ±5π/2, and so on (see Figure 6).
y = tan x
Figure 6

2222
Continuity
Another way of combining continuous functions f and g to
get a new continuous function is to form the composite
function f ° g. This fact is a consequence of the following
theorem.

2323
Continuity
Intuitively, Theorem 8 is reasonable because if x is close to
a, then g(x) is close to b, and since f is continuous at b, if
g(x) is close to b, then f(g(x)) is close to f(b).
An important property of continuous functions is expressed
by the following theorem, whose proof is found in more
advanced books on calculus.

2424
Continuity
The Intermediate Value Theorem states that a continuous
function takes on every intermediate value between the
function values f(a) and f(b). It is illustrated by Figure 7.
Note that the value N can be taken on once [as in part (a)]
or more than once [as in part (b)].
Figure 7

2525
Continuity
If we think of a continuous function as a function whose
graph has no hole or break, then it is easy to believe that
the Intermediate Value Theorem is true.
In geometric terms it says that if any horizontal line y = N is
given between y = f(a) and y = f(b) as in Figure 8, then the
graph of f can’t jump over the line. It must intersect y = N
somewhere.
Figure 8

2626
Continuity
It is important that the function f in Theorem 10 be
continuous. The Intermediate Value Theorem is not true in
general for discontinuous functions.
We can use a graphing calculator or computer to illustrate
the use of the Intermediate Value Theorem.
Figure 9 shows the graph of f in the
viewing rectangle [–1, 3] by [–3, 3] and
you can see that the graph crosses the
x-axis between 1 and 2.
Figure 9

2727
Continuity
Figure 10 shows the result of zooming in to the viewing
rectangle [1.2, 1.3] by [–0.2, 0.2].
In fact, the Intermediate Value Theorem plays a role in the
very way these graphing devices work.
Figure 10

2828
Continuity
A computer calculates a finite number of points on the
graph and turns on the pixels that contain these calculated
points.
It assumes that the function is continuous and takes on all
the intermediate values between two consecutive points.
The computer therefore connects the pixels by turning on
the intermediate pixels.

Stewart calc7e 01_08

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