Creating matrix with for loop in python

Question

I have a list with 4 elements. Each element is a correct score that I am pulling from a form. For example:

scoreFixed_1 = 1
scoreFixed_2 = 2
scoreFixed_3 = 3
scoreFixed_4 = 4

scoreFixed = [scoreFixed_1, scoreFixed_2, scoreFixed_3, scoreFixed_4]

Then, I need to add:

scoreFixed_1 to fixture[0][0]
scoreFixed_2 to fixture[0][1]
scoreFixed_3 to fixture[1][0]
scoreFixed_4 to fixture[1][1]

Hence, I need to create a triple for loop that outputs the following sequence so I can index to achieve the result above:

I have tried to use this to create this matrix, however I am only able to get the first column correct. Can anyone help?

for x in range(1):
    for y in range(1):
        for z in range(4):
            print(z, x, y)

which outputs:

There must be some logic behind this matrix that can be translated into a loop. Could you please add more information about how this matrix is formed? — 0stone0
– 0stone0, Commented Dec 2, 2021 at 16:08
As long as its in the given order that is written in the first code snippet, then it works for me — safnasfsa
– safnasfsa, Commented Dec 2, 2021 at 16:09
But how are those numbers generated? Since there' not ascending, a regular loop won't work. There must be some kinda logic behind it. — 0stone0
– 0stone0, Commented Dec 2, 2021 at 16:11
At the moment, there is no logic behind it. I simply need this to index in the correct order for another program. The first list has 4 elements, the second list has 2 elements and so does the third list. — safnasfsa
– safnasfsa, Commented Dec 2, 2021 at 16:12

RufusVS · Accepted Answer · 2021-12-02 18:17:39Z

2

Your logic does not generate the table, you want something like:

rownum = 0
for x in range(2):
    for y in range(2):
        print (rownum, x, y)
        rownum += 1

(Edit: The question has been changed, to accomplish the new desire, you want something like this:)

scoreIndex = 0
for x in range(2):
    for y in range(2):
        fixture[x][y] += scoreFixed[scoreIndex]
        scoreIndex += 1

edited Dec 2, 2021 at 18:17

answered Dec 2, 2021 at 16:16

RufusVS

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2 Comments

Erik McKelvey Over a year ago

I think you forgot to increment scoreIndex

RufusVS Over a year ago

@ErikMcKelvey I sure did! Thanks... (Edited to correct)

0stone0 · Accepted Answer · 2021-12-02 16:29:02Z

0

After your edit, it seems like we can split the 'sequence' into:

First column, regular ascending variable ( n += 1)
Second and third column, binary counter (00, 01, 10, 11)

0 0 0
1 0 1
2 1 0
3 1 1

  ^ ^------- These seem like a binary counter 
                (00, 01, 10, 11)

^------ A regular ascending variable
                ( n += 1 )

Using that 'logic' we can create a code that looks like

import itertools 

scoreFixed = 0
for i in itertools.product([0,1],repeat=2): 
    print(scoreFixed, ' '.join(map(str,i)))
    scoreFixed += 1

And wil output:

As you can test in this online demo

answered Dec 2, 2021 at 16:29

0stone0

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Comments

0x5961736972 · Accepted Answer · 2021-12-02 16:22:40Z

-1

for x in range(4):
    z = int(bin(x)[-1])
    y = bin(x)[-2]
    y = int(y) if y.isdigit() else 0
    print(x, y, z)

answered Dec 2, 2021 at 16:22

0x5961736972

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1 Comment

0x5961736972 Over a year ago

Logic is simple. After the number, the next columns represent its binary values.

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