Creating matrix with sequential numbers in Python

Question

I used two for loops for this and i stuck in here;

size = int(input("size? : "))

matrix = list(range(size**2))

for i in range(size):
    for j in range(size):
        print(j, end=" ")
     print()

and my output is;

size? : 3
0 1 2 
0 1 2 
0 1 2

How can I make it look like;

0 1 2
3 4 5
6 7 8

But it has to be work for any number that i gave

ItayB · Accepted Answer · 2019-11-16 10:45:12Z

1

size = int(input("size? : "))

for i in range(size):
    for j in range(i*size, i*size+size):
        print(j, end=" ")
    print()

answered Nov 16, 2019 at 10:45

ItayB

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2 Comments

Sam Fatu Over a year ago

Is there any way that I can make output of numbers centered. For example when I make the size 4 last two rows are moving right.

ItayB Over a year ago

yes, replace the 4th line with print('%3d' % j, end=" ")

azro · Accepted Answer · 2019-11-16 11:09:41Z

0

You can't expect to print values from 0-9 without using the matrix variable, you just print j everytime which is range of size, that's normal, you may use matrix :

for i in range(size):
    for j in range(size):
        print(matrix[i * size + j], end=" ") 
        # print(f'{matrix[i * size + j]:>2d}', end=" ") to format 2 digit numbers
    print()

This also works

for idx in range(0, len(matrix), size):
    print(*matrix[idx:idx + size])

edited Nov 16, 2019 at 11:09

answered Nov 16, 2019 at 10:41

azro

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2 Comments

Sam Fatu Over a year ago

Thank you very much. That helped a lot. And I have also a follow-up question. Is there any way that I can make output of numbers centered. For example when I make the size 4 last two rows are moving right.

azro Over a year ago

@SamFatu I've just edit for this, the '2' in >2d means 'padd befor with space to reach size of 2 at all, so if you have 3 digits at a moment use '3'

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