How to create an array using for loop while by keeping range fixed in python

Question

newarray = [x + 0.5 for x in range(1, 10)]

this code will give me following result:

newarray
[1.5, 2.5, 3.5, 4.5, 5.5, 6.5, 7.5, 8.5, 9.5]

Instead of adding 0.5 with x I want to increase my x by 0.5 for each 1 increment of x. The output suppose to be

newarray=[0.5,1,1.5,2,2.5......5.5].

Keep in mind that my range must be fix in 1 to 10. What can be better approach to make that?

Andrew Che · Accepted Answer · 2017-04-03 13:31:02Z

1

[0.5 * x for x in range(1, 12)]

Will do the thing, I'm afraid generating that array with range(1, 10) is impossible

answered Apr 3, 2017 at 13:31

Andrew Che

9688 silver badges20 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

Maybe you should write the desired result completely @TanvirHossain

result=[0.5,1,1.5,2,2.5,3,3.5,4,4.5,5,5.5]...it should not start from 0.

Look, range(1, 10) will give you a list of 9 values, and you want a list with 11 ones. @TanvirHossain

if I keep my range (0,10) is it possible to start my array from 0.5?

0, 10? Yes, [(x + 1) * 0.5 for x in range(0, 10)]