Split number string on java using regex

Question

I want to using regex on Java to split a number string. I using a online regex tester test the regex is right. But in Java is wrong.

Pattern pattern = Pattern.compile("[\\\\d]{1,4}");
String[] results = pattern.split("123456");
// I expect 2 results ["1234","56"]
// Actual results is ["123456"]

Anything do I missing?

I knows this question is boring. But I wanna to solve this problem. Answer

Pattern pattern = Pattern.compile("[\\d]{1,4}");
String[] results = pattern.split("123456");
// Results length is 0
System.out.println(results.length);

is not working. I have try it. It's will return nothing on the results. Please try before answer it.

Sincerely thank the people who helped me.

Solution:

Pattern pattern = Pattern.compile("([\\d]{1,4})");
Matcher matcher = pattern.matcher("123456");
List<String> results = new ArrayList<String>();
while (matcher.find()) {
    results.add(matcher.group(1));
}

Output 2 results ["1234","56"]

You are getting an empty array, because split returns the parts between the delimiters to split on, throwing away the delimiters themselves. Maybe this helps: stackoverflow.com/questions/2206378/… stackoverflow.com/questions/275768/… — Thilo
– Thilo, Commented Mar 16, 2012 at 8:12

Thilo · Accepted Answer · 2012-03-16 03:43:17Z

5

Pattern pattern = Pattern.compile("[\\\\d]{1,4}")

Too many backslashes, try [\\d]{1,4} (you only have to escape them once, so the backslash in front of the d becomes \\. The pattern you wrote is actually [\\d]{1,4} (a literal backslash or a literal d, one to four times).

When Java decided to add regular expressions to the standard library, they should have also added a regular expression literal syntax instead of shoe-horning it over Strings (with the unreadable extra escaping and no compile-time syntax checking).

edited Mar 16, 2012 at 3:43

answered Mar 16, 2012 at 3:35

Thilo

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1 Comment

Gordian Yuan Over a year ago

Pattern pattern = Pattern.compile("\\d{1,4}"); String[] results = pattern.split("123456"); The results length is zero.

Gordian Yuan · Accepted Answer · 2012-03-16 09:26:19Z

1

Solution:

Pattern pattern = Pattern.compile("([\\d]{1,4})");
Matcher matcher = pattern.matcher("123456");
List<String> results = new ArrayList<String>();
while (matcher.find()) {
    results.add(matcher.group(1));
}

Output 2 results ["1234","56"]

answered Mar 16, 2012 at 9:26

Gordian Yuan

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Bohemian · Accepted Answer · 2012-03-16 12:42:13Z

1

You can't do it in one method call, because you can't specify a capturing group for the split, which would be needed to break up into four char chunks.

It's not "elegant", but you must first insert a character to split on, then split:

String[] results = "123456".replaceAll("....", "$0,").split(",");

Here's the output:

System.out.println(Arrays.toString(results)); // prints [1234, 56]

Note that you don't need to use Pattern etc because String has a split-by-regex method, leading to a one-line solution.

answered Mar 16, 2012 at 12:42

Bohemian♦

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