Converting User Input to Integer with Custom Error Message

Question

I am currently working on a program which accepts a user input through the JOptionPane window. My goal is to create an if statement which validates the user input as an integer. I've tried the Integer.parseInt method but that just throws an exception, so I cannot display my own JOptionPane window informing the user of the mistake. I'm very new to programming and cannot think of another way to convert the string to an integer (or at least another way that works) for use in the if statement. Ideas?

Thanks!

Post the code you have tried. It's hard for us to help you when we don't know what you did. — Tony
– Tony, Commented Mar 8, 2012 at 5:11
The easiest thing would be to catch the exception and handle it. — trutheality
– trutheality, Commented Mar 8, 2012 at 5:14

Juvanis · Accepted Answer · 2012-03-08 05:15:18Z

2

If you are to get an integer somehow after the JOptionPane message is displayed, you may want to take a look at this code which continuously prompts the user to enter a valid integer:

int number = 0;
boolean ok = false;
String input = "";

while(!ok)
{
    try
    {
        number = Integer.parseInt( input );
        ok = true;
    }
    catch(Exception e)
    {
        // Change your JOptionPane message here to warn the user.
    }
}

answered Mar 8, 2012 at 5:15

Juvanis

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