Convert from binary back to its string value in Java

Question

Currently, I have a String with the value "0100100001101001" (this is binary for the word 'Hi'). I'm trying to figure out how to take that string and convert it back into the word "Hi"

I used

String s = "Hi";   
byte[] bytes = s.getBytes();   
StringBuilder binary = new StringBuilder();   
for (byte b : bytes)   
{      
    int val = b;      
    for (int i = 0; i < 8; i++)      
    {         
        binary.append((val & 128) == 0 ? 0 : 1);         
        val <<= 1;      
    }         
}   
s = binary.toString();

found on: Convert A String (like testing123) To Binary In Java

Any help would be much appreciated. Thanks in advance.

""0100100001101001" (this is binary for the word 'Hi')" In what character set? (Yes, I know, ASCII and most others, because it happens that "H" and "i" are fairly common amongst them. But the point stands.) — T.J. Crowder
– T.J. Crowder, Commented Jan 23, 2012 at 23:25

Shad · Accepted Answer · 2012-01-23 23:29:32Z

2

Something like..

BigInteger val = new BigInteger("0100100001101001", 2);
String hi = new String(val.toByteArray());

edited Jan 23, 2012 at 23:29

Shad

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answered Jan 23, 2012 at 23:27

izb

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1 Comment

Ted Hopp Over a year ago

+1 It might be appropriate to include an encoding specification when converting bytes to a string; e.g.: String hi = new String(val.toByteArray(), "UTF-8");. There's also the small problem of byte ordering, but OP is on his own for this.

calebds · Accepted Answer · 2012-01-24 01:12:14Z

1

Another solution, for variety. Uses (char) casting. Take s to be the binary String:

String result = "";
for (int i = 0; i < s.length(); i += 8) {
    result += (char) Integer.parseInt(s.substring(i, i + 8), 2);
}

answered Jan 24, 2012 at 1:12

calebds

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