Accessing a PHP array

Question

I'm sure this has been asked before, but I can't seem to find the answer.

To that end, I have an array that looks like this:

Array
(
    [0] => Array
        (
            [status] => active
            [sid] => 1
        )

    [1] => Array
        (
            [status] => expired
            [sid] => 2
        )

)

What I'd like to be able to do is type $arrayName["active"] and it return the SID code. I will be using this like a dictionary object of sorts. It's like I need to reindex the array so that it is the key/value pair that I need. I was just wondering if there was an easier way to do it.

What if there's 3 subarrays and 2 are 'active'? an array key can only point to one "value" (even if that value is another array). — Marc B
– Marc B, Commented Jan 22, 2012 at 7:01

Carl Zulauf · Accepted Answer · 2012-01-22 07:07:32Z

3

You should convert your nested arrays into a single associative array. Something like this should take your example and turn it into an associative array:

$assoc_array = array();
foreach( $example_array as $values ) {
  $assoc_array[$values["status"]] = $values["sid"];
}

You can then access the sid for a given status by using $assoc_array["expired"] (returns 2)

answered Jan 22, 2012 at 7:07

Carl Zulauf

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1 Comment

dpluscc Over a year ago

This is what I ended up doing - now I can access the array like I want. Thanks!

Freyja · Accepted Answer · 2012-01-22 07:14:56Z

After seeing the others' solutions, I realize this might be bit of an overkill, but I'm still just gonna throw it out there:

$foo = array(
  array('status' => 'active', 'sid' => 1),
  array('status' => 'expired', 'sid' => 2),
);

// Get all the 'status' elements of each subarray
$keys = array_map(function($element) {
  return $element['status'];   
}, $foo);

// Get all the 'sid' elements of each subarray
$values = array_map(function($element) {
  return $element['sid'];
}, $foo);

// Combine them into a single array, with keys from one and values from another
$bar = array_combine($keys, $values);

print_r($bar);

Which prints:

Array
(
    [active] => 1
    [expired] => 2
)

Manual pages:

donutdan4114 · Accepted Answer · 2012-01-22 07:12:13Z

1

You can use this function:

  function findActive($my_array){

    foreach($my_array as $array){
      foreach($array as $val){
        if($val['status']==='active'){
          return $val['sid'];
        }
      }
    }

    return false;

  }

answered Jan 22, 2012 at 7:12

donutdan4114

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Comments

Matt Lo · Accepted Answer · 2012-01-22 07:06:58Z

0

access it via a loop or directly.

if($arrayName[0]['status'] == "active") {
   echo $arrayName[0]['sid'];
}

If you want to check all the SIDs

foreach($arrayName as $item) {
  if($item['status'] == "active") {
     echo $item['sid'];
  }
}

A more direct approach is just putting the loop in a function and return an array of all active session IDs

answered Jan 22, 2012 at 7:06

Matt Lo

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Comments

Sudhir Bastakoti · Accepted Answer · 2012-01-22 07:09:27Z

0


$sidArr = array();
foreach($yourArr as $val) {
  if("active" == $val["status"]) {
    array_push($sidArr, $val["sid"]);
  }
}

answered Jan 22, 2012 at 7:09

Sudhir Bastakoti

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Comments

rauschen · Accepted Answer · 2012-01-22 07:21:23Z

0

reindex would be the best

$arrayName = array()
foreach ($data_array as $data)
   $arrayName[$data['status']]=$data['sid'];

Or use a function

function get_sid($status)
{
    global $data_array;
    foreach ($data_array as $data) {
        if ($data['status']==$status)
             return $data['sid'];
    }
    return false;    
}

answered Jan 22, 2012 at 7:21

rauschen

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