integer expression expected testing or condition in if else bash scripts

Question

In a shell script I wrote following lines gave error during execution of script

if [ p -eq 35 -o p -eq 70 ]; then
echo "Sleeping ....zzz ........zzzz......."
sleep 5

get following error

/d2.sh: line 6: [: p: integer expression expected

Sven Marnach · Accepted Answer · 2012-01-12 12:32:57Z

2

You probably want $p instead of p:

if [ $p -eq 35 -o $p -eq 70 ]; then
    ...

answered Jan 12, 2012 at 12:32

Sven Marnach

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3 Comments

choroba Over a year ago

You can use variable names without $ only in (( ... )) arithmetic expressions.

Gordon Davisson Over a year ago

@l0b0: No, [[ ]] still requires $ to expand variables. @choroba: Note that you need to use different operators inside (( )): ==, <, >, || etc instead of -eq, -lt, -gt, -o...

Rajasekhar Over a year ago

Thank you @GordonDavisson for your nice advice... as I am searching so many websites how can I get rid of this integer problem.

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