How can I declare a list of objects in php as a private instance variable?
In Java the declaration would look something like this
private ArrayList<Object> ls
and the constructor would have this
ls = new ArrayList<Object>();
Thanks
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2 Answers
PHP allocates memory dynamically and what's more, it doesn't care what sort of object you store in your array.
If you want to declare your array before you use it something along these lines would work:
var $myArray = array();
Then you can store any object you like in your variable $myArray. Many people find this a strange concept to grasp after working in a strict language like java.
4 Comments
user1114
What is the difference between var $myArray = array() and $array = array()
boobiq
there is no difference, that's only name of that variable, you can use whatever you want :) it's like
ls in your questionuser1114
I meant whether I use 'var' or not before the variable.
boobiq
@user1114 it's deprecated way to declare class variables (used in PHP 4), in PHP 5 you should use public/private..
you can declare it in class like
private $array = array();
and append objects (or anything) to that array like
$array[] = some object
1 Comment
Gaʀʀʏ
You can also use it associatively, by saying
$array['key'] = value;