I have an 2-D array and i wanted to access the particular element of this array using pointer to array something like this below
main()
{
int a[][4]={{2 ,0 ,0 ,2},{41 ,0, 0, 9}};
int (*p)[4]=a;
printf("%d",*p[0]);
}
This gives me the first element of Ist 1-d array but now access 2nd element of 1-d array using pointer to array?
You can simply access the elements of your 2d arrays like this:
printf("%d", a[0][1]); /* prints second item of first array */
a[x][y] gets compiled into *(a+x*4+y).
The elements are accessed using the corresponding row and column numbers.
If u have to access the second element of the first row in the 2-D array mentioned above, then you can use
printf("%d",a[2][1]);
int a[2][4]={{2 ,0 ,0 ,2},{41 ,0, 0, 9}};
int (*p)[4]=a;
for (i = 0; i < 2; i++)
for (j = 0; j < 4; j++)
printf("%d\n", p[i][j]);
You can access the array elements with p as if it was a.
The reason for that is simply because when you use the name a in a value context, its type is already int (*)[4], so the same type as p.
Note that the p[i][j] form in C is equivalent to *(*p + i) + j).
