Parsing Query String in node.js

There's also the QueryString module's parse() method:

var http = require('http'),
    queryString = require('querystring');

http.createServer(function (oRequest, oResponse) {

    var oQueryParams;

    // get query params as object
    if (oRequest.url.indexOf('?') >= 0) {
        oQueryParams = queryString.parse(oRequest.url.replace(/^.*\?/, ''));

        // do stuff
        console.log(oQueryParams);
    }

    oResponse.writeHead(200, {'Content-Type': 'text/plain'});
    oResponse.end('Hello world.');

}).listen(1337, '127.0.0.1');

Starting with Node.js 11, the url.parse and other methods of the Legacy URL API were deprecated (only in the documentation, at first) in favour of the standardized WHATWG URL API. The new API does not offer parsing the query string into an object. That can be achieved using the querystring.parse method:

// Load modules to create an http server, parse a URL and parse a URL query.
const http = require('http');
const { URL } = require('url');
const { parse: parseQuery } = require('querystring');

// Provide the origin for relative URLs sent to Node.js requests.
const serverOrigin = 'http://localhost:8000';

// Configure our HTTP server to respond to all requests with a greeting.
const server = http.createServer((request, response) => {
  // Parse the request URL. Relative URLs require an origin explicitly.
  const url = new URL(request.url, serverOrigin);
  // Parse the URL query. The leading '?' has to be removed before this.
  const query = parseQuery(url.search.substr(1));
  response.writeHead(200, { 'Content-Type': 'text/plain' });
  response.end(`Hello, ${query.name}!\n`);
});

// Listen on port 8000, IP defaults to 127.0.0.1.
server.listen(8000);

// Print a friendly message on the terminal.
console.log(`Server running at ${serverOrigin}/`);

If you run the script above, you can test the server response like this, for example:

curl -q http://localhost:8000/status?name=ryan
Hello, ryan!

require('url').parse('/status?name=ryan', {parseQueryString: true}).query

returns

{ name: 'ryan' }

ref: https://nodejs.org/api/url.html#url_urlobject_query

node -v v9.10.1

If you try to console log query object directly you will get error TypeError: Cannot convert object to primitive value

So I would suggest use JSON.stringify

const http = require('http');
const url = require('url');

const server = http.createServer((req, res) => {
    const parsedUrl = url.parse(req.url, true);

    const path = parsedUrl.pathname, query = parsedUrl.query;
    const method = req.method;

    res.end("hello world\n");

    console.log(`Request received on: ${path} + method: ${method} + query: 
    ${JSON.stringify(query)}`);
    console.log('query: ', query);
  });


  server.listen(3000, () => console.log("Server running at port 3000"));

So doing curl http://localhost:3000/foo\?fizz\=buzz will return Request received on: /foo + method: GET + query: {"fizz":"buzz"}

Another way to get query params without require'ing any modules:

// ...
var server = http.createServer(function (request, response) {

  const requestUrl = new URL(request.url, `http://${request.headers.host}`);
  // Note that searcParams is not a simple JS object.
  // So to get parameter value by its name one should use access methods:
  const nameValue = requestUrl.searchParams.get('name');

  response.writeHead(200, {"Content-Type": "text/plain"});    
  response.end("Hello World\n");
});
// ...

See http.IncomingMessage.url and URLSearchParams for details.