I would like to remove all the elements in the String array for instance:
String example[]={"Apple","Orange","Mango","Grape","Cherry"};
Is there any simple to do it,any snippet on it will be helpful.Thanks
6 Answers
If example is not final then a simple reassignment would work:
example = new String[example.length];
This assumes you need the array to remain the same size. If that's not necessary then create an empty array:
example = new String[0];
If it is final then you could null out all the elements:
Arrays.fill( example, null );
- See: void Arrays#fill(Object[], Object)
- Consider using an
ArrayListor similar collection
1 Comment
milanchandna
First approach(reassignment) should only be preferred if it has to be done once or twice or few times. Otherwise every time you will end up allocating memory for new arrays. Also Second approach can not be used for primitive arrays.
example = new String[example.length];
If you need dynamic collection, you should consider using one of java.util.Collection implementations that fits your problem. E.g. java.util.List.
Comments
Reassign again. Like example = new String[(size)]
Comments
list.clear() is documented for clearing the ArrayList.
list.removeAll() has no documentation at all in Eclipse.
Comments
Usually someone uses collections if something frequently changes.
E.g.
List<String> someList = new ArrayList<String>();
// initialize list
someList.add("Mango");
someList.add("....");
// remove all elements
someList.clear();
// empty list
An ArrayList for example uses a backing Array. The resizing and this stuff is handled automatically. In most cases this is the appropriate way.
Comments
Just Re-Initialize the array
example = new String[size]
or If it is inside a running loop,Just Re-declare it again,
**for(int i=1;i<=100;i++)
{
String example = new String[size]
//Your code goes here``
}**
String[5]to beString[0]?