want to parse string input for int using sstream

Question

I am new to c++ programming. I have read how parsing can be done in SO questions using vector(Int tokenizer).But I have tried the following for array. I am able to parse only one number from string. If input string is "11 22 33 etc".

#include<iostream>
#include<iterator>
#include<vector>
#include<sstream>

using namespace std;

int main()
{

int i=0;
string s;
cout<<"enter the string of numbers \n";
cin>>s;
stringstream ss(s);
int j;
int a[10];
while(ss>>j)
{

    a[i]=j;
    i++;
}
for(int k=0;k<10;k++)
{
    cout<<"\t"<<a[k]<<endl;
}

}

If I give input as "11 22 33"

output

11
and some garbage values.

If i have initialized stringstream ss("11 22 33"); then its working fine. What am I doing wrong?

oh whatever · Accepted Answer · 2011-12-15 07:50:34Z

4

The problem is that:

cin>>s;

Reads one space separated word into s. So only 11 goes into s.

What you want is:

std::getline(std::cin, s);

Alternatively you can read numbers directly from std::cin

while(std::cin >> j) // Read a number from the standard input.

edited Dec 15, 2011 at 7:50

oh whatever

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answered Dec 15, 2011 at 7:47

Loki Astari

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Comments

jfs · Accepted Answer · 2011-12-15 07:50:29Z

0

It seems cin>>s stop at the first whitespace. Try this:

cout << "enter the string of numbers" << endl;
int j = -1;
vector<int> a;
while (cin>>j) a.push_back(j);

answered Dec 15, 2011 at 7:50

jfs

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Comments

Sanish · Accepted Answer · 2011-12-15 07:59:32Z

0

We can use cin to get strings with the extraction operator (>>) as we do with fundamental data type variables

cin >> mystring;

However, as it has been said, cin extraction stops reading as soon as if finds any blank space character, so in this case we will be able to get just one word for each extraction.

From http://www.cplusplus.com/doc/tutorial/basic_io/

So you have to use getline()

string s;
cout<<"enter the string of numbers \n";
getline(cin, s);

answered Dec 15, 2011 at 7:59

Sanish

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