I am trying to sort $ar1 by the descending order values of $ar2. Nothing is happening.
$ar1 = array($arperc);
$ar2 = array($arid);
array_multisort($ar1, $ar2);
print_r($ar1);
What am I missing?
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2Could you give us examples for the values of $arperc and $arid?Justin Lucas– Justin Lucas2011-12-07 21:53:58 +00:00Commented Dec 7, 2011 at 21:53
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1your arguments are the wrong way around :Dthwd– thwd2011-12-07 21:54:18 +00:00Commented Dec 7, 2011 at 21:54
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1You really need to provide some example data to allow us to solve that.. But it seems that you send in an array with just one value? You probably want to just create a copy with $ar1 = $arperc; if you don't want to sort the original array.MatsLindh– MatsLindh2011-12-07 21:54:32 +00:00Commented Dec 7, 2011 at 21:54
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Are these single element arrays? Are these multi-dimensional arrays? We don't know. These is no minimal reproducible example.mickmackusa– mickmackusa ♦2023-04-03 09:44:12 +00:00Commented Apr 3, 2023 at 9:44
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1 Answer
If you want to use the elements of $ar2 as sorting keys, you need to change the order of arguments to array_multisort:
array_multisort($ar2, $ar1);
This will sort $ar2 in ascending order, and also change the order of $ar1 elements exactly as the order of $ar2 is changed by the sorting. To change the order to descending:
array_multisort($ar2, SORT_DESC, $ar1);
1 Comment
ygoe
Yes, the PHP documentation is really terrible in explaining how to use that function. I've also got that wrong. And it always worked, until it didn't. So if the first array is also being sorted, it must be an unintended side effect. stackoverflow.com/q/75836843/143684