Ruby: string float to integer

Question

I want this:

'5.6535'.something => 56
'5.657'.something => 566
'5.3'.something => 530
'5'.something => 500

and so on...

My "string" float ranges from 1..9 and I want them to convert to an integer with three digets.

Thanks!

Kieran

Your string always contains only one digit before separator? — WarHog
– WarHog, Commented Nov 11, 2011 at 22:03

Peter · Accepted Answer · 2011-11-11 22:01:20Z

3

strings.each do |str|
  puts (str.to_f * 100).floor
end

Substitute round or ceil for floor depending on what behavior you want with rounding.

answered Nov 11, 2011 at 22:01

Peter

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4 Comments

Thanks, it is really that simple! Found this as well: ruby-doc.org/core-1.9.3/String.html#method-i-to_f

This doesn't guarantee three digits.

@MarkByers, sure. question needs clarification if this matters.

@MarkByers Just edited the question. Thanks for pointing this out.

Mark Byers · Accepted Answer · 2011-11-11 22:03:03Z

1

(x + '000').scan(/\d/)[0,3].join('').to_i

answered Nov 11, 2011 at 22:03

Mark Byers

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