Python Variables and Strings

Question

I need to know if a variable in Python is a string(name) or a number. I want to check out the degree of graphs, however I need to know if "i" iterator, is a number inside of the string or a name inside of the string, showing the degree of graphs at the end.

Is there something wrong in this code?

import csv, sys
import networkx as nx

def ministro_lei():

    stf = csv.reader(open('resultset.csv', 'rb'), delimiter=',', quotechar='|')
    eds = [(i[0],i[1],i[2]) for i in stf]
    G = nx.DiGraph(nome='ministro_lei')
    G.add_weighted_edges_from(eds)
    for i in G.degree():
        if isinstance(i,str):
            print (" This is a name:", i)
        elif isinstance(i, int):
            print ("This is a number: ", i)
        else:
            raise ValueError 
    return G, eds

ministro_lei = ()

Here lies some examples of outs:

  "MIN. OCTAVIO GALLOTTI",53,109
  "MIN. SYDNEY SANCHES",13,109
  "MIN. JOAQUIM BARBOSA",101,108

Please any help? Thanks

Could you be more precise in what you are asking? It's totally unclear at least for me what do you want. — Artsiom Rudzenka
– Artsiom Rudzenka, Commented Nov 11, 2011 at 12:36
Your "normal" return at the end of the method ministro_lei returns two variables. However, there are two more return (i) lines within the loops, that return single variables. This structure will never pass past the first iteration of the for-loop. Is this what you want? — eumiro
– eumiro, Commented Nov 11, 2011 at 12:37
If one of the answers works for you, you should accept it (click on the greet checkmark by it). — Ethan Furman
– Ethan Furman, Commented Oct 4, 2012 at 17:01

unutbu · Accepted Answer · 2011-11-11 12:37:50Z

2

They must be strings since ",".join(i) would have returned a TypeError if i were an int.

But, in general, to find out the type of a variable, use type:

print(type(i))

answered Nov 11, 2011 at 12:37

unutbu

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2 Comments

joel goldstick Over a year ago

it looks to me like i is a list. Not a string or an integer.

unutbu Over a year ago

@joelgoldstick: Hm. The code has changed after I posted my answer.

bpgergo · Accepted Answer · 2011-11-11 12:40:47Z

1

I hope this helps

>>> s = 'hello'
>>> type(s)
<type 'str'>
>>> type(s) is str
True
>>> n = 6
>>> type(n)
<type 'int'>
>>> type(n) is int
True

answered Nov 11, 2011 at 12:40

bpgergo

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