How can I resolve type traits in gdb Python API?

Question

Consider a type like

#include <type_traits>
template<typename T>
struct Foo {
    std::remove_cv_t<T> m;
};

which uses a type trait to deduce the type of one of its members from a template parameter. This type may then be used as follows:

Foo<const int> f;
f.m = 42;          // type of f.m is std::remove_cv_t<const int>,
                   // which resolves to int; break on this line

When trying to inspect the type of f.m wit gdb's Python API, it seems I only get incomplete information.

(gdb) python-interactive
>>> print(gdb.parse_and_eval('f')['m'].type)
std::remove_cv_t

This is not very helpful. It does not tell me what template arguments remove_cv_t was instantiated with, nor which underlying type the instantiated trait resolves to.

How can I determine through the Python API that the resolved type of f.m in this case is int?

ComicSansMS · Accepted Answer · 2025-09-16 16:09:43Z

3

The API function you are looking for is strip_typedefs():

Function: Type.strip_typedefs ()

Return a new gdb.Type that represents the real type, after removing all layers of typedefs.

(gdb) python-interactive
>>> print(gdb.parse_and_eval('f')['m'].type.strip_typedefs())
int

answered Sep 16 at 16:09

ComicSansMS

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