VS Code snippet - how to get the relative_filepath without the file extension

Question

How can I get the relative_filepath without the extension and backslash change ?

I found two transforms:

"${RELATIVE_FILEPATH/[\\]/\//g/}"
"${RELATIVE_FILEPATH/(.js)//}"

If the relative file path is \aaa\bbb\ccc.js

I tried this:

/${RELATIVE_FILEPATH/((.js))}|/[\\]/${1://}${2://g/}/}

I want to get text like this: /aaa/bbb/ccc

Thank you.

thank for correct words.

이병옥
– 이병옥

2025-02-24 01:43:04 +00:00
Commented Feb 24 at 1:43 — 이병옥
– 이병옥, Commented Feb 24 at 1:43

Mark · Accepted Answer · 2025-02-22 03:24:40Z

0

Try this snippet:

"Remove extension and swap to forward slash": {
    "prefix": "t2",
    "body": [
        // "${RELATIVE_FILEPATH}",
        "/${RELATIVE_FILEPATH/.js|(\\\\)/${1:+\/}/g}",
    ],
    "description": ""
},

Note the double escapes in .js|(\\\\) are necessary.
And I added the + to the ${1:+\/}.

answered Feb 22 at 3:24

Mark

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1 Comment

이병옥 Feb 24 at 1:27

thank you for your help. Thanks to you you saved me time. Your code works correctly. ^^

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