How can I create a url pattern for two parameters where the first parameter contains a forward slash as part of its contents:
da/ta1=/data2
Intially I had the following pattern:
(r'^view/(?P<item_id>\w+=)/(?P<changekey>\w+)/$', 'view'),
However this pattern does not match because of the first forward slash which is part of the parameter data.
Assuming you construct the url yourself, you could use quote_plus to encode the inline forward slash:
>>> '/'.join([urllib.quote_plus(d) for d in ['da/ta1', 'data2']])
'da%2Fta1/data2'
And to decode:
>>> urllib.unquote_plus('da%2Fta1/data2')
'da/ta1/data2'
To then match your data, your pattern could be changed to the construct found below. For the first parameter, this matches everything up to the = character; the second parameter is expected to be alphanumerical.
(r'^view/(?P<item_id>[^=]+)=/(?P<changekey>\w+)/$', 'view')
Django Admin does have the same problem with slashes in parameters. To fix this, Django uses its own quote function:
from django.contrib.admin.utils import quote
quote(param1)
In the view itself:
unquote(self.kwargs.get('param1'))
