PHP - Concatenating two variables

Question

I'm a newbie stumped on the following. If I'm including an external file on a page that contains the following variable:

$blurb_78 = "Lorem ipsum dolor.";

How can I echo $blurb_78 on the local page? (where the 78 part is a generated article ID set to a variable labeled, $id)

The following doesn't work:

echo $blurb_.$id;

Thanks much for your help.

The phrasing is creating some confusion: do you want the output to be "$blurb_78" or "Lorem ipsum dolor."? I answered for the former; many for the latter. — cbrandolino
– cbrandolino, Commented Oct 4, 2011 at 13:41

Bas Slagter · Accepted Answer · 2011-10-04 14:10:35Z

7

I think you mean a variable variable name like it is mentioned at the Variable variables page on the PHP site. In your case this should work fine:

echo ${'blurb_'.$id};

But I highly doubt your approach on this one.

edited Oct 4, 2011 at 14:10

answered Oct 4, 2011 at 13:34

Bas Slagter

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Comments

Arda · Accepted Answer · 2011-10-04 13:32:55Z

0

Try making an array:

$blurb = array();

$blurb[78] = "Lorem ipsum";

echo $blurb[$id];

answered Oct 4, 2011 at 13:32

Arda

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2 Comments

cbrandolino Over a year ago

OP wanted to output the vas's name.

cbrandolino Over a year ago

... And I was wrong. I'm going to upvote a random other question of yours, since I downvoted this more than 7 minutes ago.

Matías Fidemraizer · Accepted Answer · 2011-10-04 13:33:28Z

0

You should use an associative array instead of variables in your case.

Check this article in PHP official documentation:

http://php.net/manual/es/language.types.array.php

answered Oct 4, 2011 at 13:33

Matías Fidemraizer

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Comments

cbrandolino · Accepted Answer · 2011-10-04 13:35:09Z

0

This is your answer:

 echo '$blurb_'.$id;

Still, an associative array is the way to go.

answered Oct 4, 2011 at 13:35

cbrandolino

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Comments

Mark Northrop · Accepted Answer · 2011-10-04 13:36:58Z

0

Try

<?php
$blurb_78 = 'Lorem ipsum dolor.';
$id = 78;
echo ${'blurb_'.$id};
?>

answered Oct 4, 2011 at 13:36

Mark Northrop

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Comments

Shef · Accepted Answer · 2011-10-04 13:45:22Z

0

echo ${'blurb_'.$id};

Demo

Read more on the variable variables article.

edited Oct 4, 2011 at 13:45

answered Oct 4, 2011 at 13:36

Shef

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3 Comments

cbrandolino Over a year ago

Not really. Op wanted to output the string "$blurb_78" with the "78" part given as a variable.

Shef Over a year ago

@cbrandolino Huh? What is mine doing? I have even linked to a demo page so you can see how it's working. Edit: I see what you meant. I don't think OP was that PHP illiterate.

cbrandolino Over a year ago

It's echoing the var's value, while I thought OP wanted its name to be displayed.

pettys · Accepted Answer · 2020-05-07 16:45:47Z

0

This should work for concatenating two variables:

echo ${'blurb_'.$id}

edited May 7, 2020 at 16:45

pettys

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answered Oct 4, 2011 at 13:38

Dave

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