I tried to look through a lot of similar questions but I have a specific query. I have two or more sets of strings (space separated values). I want to loop through
firstString="f1 f2 f3 f4"
secondString="s1 s2 s3 s4"
I want something like
f1-s1
f2-s2
f3-s3
f4-s4
(in a single loop)
I must be able to take the positional value of the second and further arrays in a single loop.
Well, if you first replace all spaces with a new-line, using tr so that you have each value on a separate line, then paste will solve your problem:
$ cat a b
f1
f2
f3
f4
s1
s2
s3
s4
$ paste -d- a b
f1-s1
f2-s2
f3-s3
f4-s4
Pure bash solution:
#!/bin/bash
firstString='f1 f2 f3 f4'
secondString='s1 s2 s3 s4'
read -ra FIRST <<< "$firstString"
read -ra SECOND <<< "$secondString"
index=0
for i in ${FIRST[@]}
do
echo $i-${SECOND[$index]}
((index++))
done
You could make use of bash built-in arrays:
first=(f1 f2 f3 f4)
second=(s1 s2 s3 s4)
for (( i = 0; i < ${#first[*]}; i++ )); do
echo ${first[$i]}-${second[$i]}
done
str="f1 f2 f3 f4"; strArr=($str). It's that simple. As for the more than 2 sets, just add "third", "fourth" and so on... :)see the test with awk below:
kent$ firstStr="f1 f2 f3 f4"
kent$ secondStr="s1 s2 s3 s4"
#now we have two variable
kent$ echo 1|awk -v two=$secondStr -v one=$firstStr '{split(one,a);split(two,b);for(i=1;i<=length(a);i++)print a[i]"-"b[i]}'
f1-s1
f2-s2
f3-s3
f4-s4
You can easily do it in a portable manner:
set $firstString
for s in $secondString; do
echo "$1-$s"
shift
done
