Swift: Sort array of objects alphabetically, but Put Objects Matching a particular Field First

Question

I have this struct of locations:

struct Location: Identifiable, Codable {
    var id: String
    var name: String
    var country: String
}

I can easily sort this by name:

self.userData = self.userData.sorted(by: {$0.name < $1.name })

But I also want the ability to put locations with a particular country first in the list.

I tried this:

self.userData.sorted(by: { ($0.country == "United States"), ($0.name < $1.name) })

but I get an error "Consecutive statements on a line must be separated by ;".

How can I sort alphabetically by a particular country first? Then sort the remaining locations alphabetically by the name property.

rob mayoff · Accepted Answer · 2023-02-09 20:06:34Z

2

You probably still want to sort by name if both locations have a country of "United States".

let topCountries: Set<String> = ["United States"]

userData.sorted { a, b in
    switch (topCountries.contains(a.country), topCountries.contains(b.country)) {
    case (true, false): return true
    case (false, true): return false
    default: return a.name < b.name
    }
}

answered Feb 9, 2023 at 20:06

rob mayoff

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Comments

gnasher729 · Accepted Answer · 2023-02-09 20:10:17Z

0

Look at the full syntax of passing a closure. You are using a shortcut for the special case that the closure consists of one return statement only. Expand it to the full closure syntax where you can use arbitrary code, then write the code you need.

answered Feb 9, 2023 at 20:10

gnasher729

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hoptown · Accepted Answer · 2023-02-11 15:53:22Z

0

The solution @rob mayoff gave worked. Here is my final piece of code:

let topCountries: Set<String> = ["United States"] // or the user's country
        
    filteredLocations = allLocations.filter { $0.name.contains(searchText) }.sorted { a, b in
                switch (topCountries.contains(a.country), topCountries.contains(b.country)) {
                    case (true, false): return true
                    case (false, true): return false
                    default: return a.name < b.name
                }
            }

answered Feb 11, 2023 at 15:53

hoptown

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