From the given array of objects how to filter the expected output
let a = [{name:'Hari',age:2},{name:'Chana',age:4},{name:'Like',age:5}]
let b = [{name:'Chana',age:14},{name:'Like',age:15}];
I tried this but not working;
let c =a.filter(elm => b.find(el => el.name === elm.name));
expected output is [{name:'Hari',age:2}]
You need to change little modification inside code of filter and final code will be :
let a = [{name:'Hari',age:2},{name:'Chana',age:4},{name:'Like',age:5}]
let b = [{name:'Chana',age:14},{name:'Like',age:15}];
let c = a.filter(elm => !b.find(el => el.name === elm.name));
console.log(c);Result will be:
[ { name: 'Hari', age: 2 } ]
Check if the result of filter === 0
let a = [{name:'Hari',age:2},{name:'Chana',age:4},{name:'Like',age:5}]
let b = [{name:'Chana',age:14},{name:'Like',age:15}];
let c = a.filter(x => b.filter(y => y.name === x.name).length === 0);
console.log(c);
b.filter() needs to go through the entire array, by keeping .find() or using something like .every() or .some() instead (which all exit early), you can avoid looping the entire array if you find a matching name earlier on in b
!b.find(...). But I wouldn't use.find()here as you're after a boolean, instead, you could use!b.some(...)