JavaScript - how can I create a function which can remove numbers from array?

Question

I've tried this

function removeFromArray(manyMoreArgs, number) {
  let i = 0;
  while (i < manyMoreArgs.length) {
    if (manyMoreArgs[i] === number) {
      manyMoreArgs.splice(i, 1);
    } else {
      i++;
    }
  }
  return manyMoreArgs;
}
console.log(removeFromArray([1, 2, 3, 4], 3)); // result = [1, 2, 4] this removes 3 from array. it works! but then >>
console.log(removeFromArray([1, 2, 3, 4], 3, 2)); // result = [1, 2, 4] this removes 3 from array too but I also want to remove 2 from array

What should I do if I want to remove numbers from array?

derpirscher · Accepted Answer · 2022-12-16 09:28:13Z

3

You could either define your numbers parameter as an array

function removeFromArray(manyMoreArgs, numbers) {
  let i = 0;
  while (i < manyMoreArgs.length) {
    if (numbers.includes(manyMoreArgs[i])) {
      manyMoreArgs.splice(i, 1);
    } else {
      i++;
    }
  }
  return manyMoreArgs;    
}

console.log(removeFromArray([1, 2, 3, 4], [3]));// result = [1, 2, 4] this removes 3 from array. it works! but then >>
console.log(removeFromArray([1, 2, 3, 4], [3, 2]));// result = [1, 2, 4] this removes 3 from array too but I also want to remove 2 from array

or as a variadic argument

function removeFromArray(manyMoreArgs, ...numbers) {
  let i = 0;
  while (i < manyMoreArgs.length) {
    if (numbers.includes(manyMoreArgs[i])) {
      manyMoreArgs.splice(i, 1);
    } else {
      i++;
    }
  }
  return manyMoreArgs;    
}

console.log(removeFromArray([1, 2, 3, 4], 3));// result = [1, 2, 4] this removes 3 from array. it works! but then >>
console.log(removeFromArray([1, 2, 3, 4], 3, 2));// result = [1, 2, 4] this removes 3 from array too but I also want to remove 2 from array

answered Dec 16, 2022 at 9:28

derpirscher

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6 Comments

0xtrvkc Over a year ago

oh big thanks, it works now! I have to take a look what .include is. (i'm a beginner, I've never seen this syntax before)

derpirscher Over a year ago

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

derpirscher Over a year ago

If it works, feel free to accept the answer ...

0xtrvkc Over a year ago

I click the ✔ it turns green then it turns back to grey again automatically did I miss something?

derpirscher Over a year ago

because you accepted another answer ...

|

Hrusikesh · Accepted Answer · 2022-12-16 09:45:42Z

1

I think you can make use of a JavaScript function that takes in these two arrays and filters the first to contain only those elements that are not present in the second array. And then return the filtered array.

    const removeNum = (arr,...numbers) =>{
       const arr2 = [...numbers]
       console.log(arr2); 
       numbers = arr.filter(el => {
          return arr2.indexOf(el) === -1;
        });;
       console.log(numbers);   
    }

removeNum([1, 2, 3, 4], 3, 2)

answered Dec 16, 2022 at 9:45

Hrusikesh

6936 silver badges16 bronze badges

1 Comment

0xtrvkc Over a year ago

thank you, today I learn new things (.filter/.include) you gave me new perspective

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