Filter a pattern in middle of a string of an array JAVASCRIPT

Question

I have an array, I want to filter out all the paths which are in form of /__/:__Id. I am currently using .endsWith property but I want to make a generic code which recognizes the pattern and doesn't return paths in pattern of /routename**/:nameId**

const ROUTES = [ { path: "/" }, { path: "/faqs" }, { path: "/contactus" }, { path: "/pricing" }, { path: "/products" }, { path: "/careers/:jobId" }, { path: "/careers" }, { path: "/about-us" }, { path: "/features" }, { path: "/usecase/:usecaseId" } ];

const selectedRoutes = ROUTES.map( (item) => {
  if (item.path === "/")
    return "";
  else
    return item.path;
}).filter( (item) => { return !item.endsWith("Id")}); 

console.log(selectedRoutes)

Could you try to clarify the question and also the code a little? You say I want to filter out all the paths which are in form of /__/:__Id and then doesn't return paths in pattern of /routename**/:nameId** - these two statements seem to contradict each other - or I am misunderstand you. In any case; clarification would help :) — Joel Peltonen
– Joel Peltonen, Commented Dec 13, 2022 at 9:30

Nitheesh · Accepted Answer · 2022-12-16 10:17:40Z

1

You can achieve this requirement with the help of below RegExp

^\/(\\w)+\/:.*Id\/?$

RegEx explanation :

^\/ - Match the string start with forward slash
(\\w)+ - Matches the word characters (a-z, 0-9 and underscore), + is used to match the word one or more time.
\/? - Matches zero or one forward slash
$ - Denotes end of a string

Live Demo :

const ROUTES = [ { path: "/" }, { path: "/faqs" }, { path: "/contactus" }, { path: "/pricing" }, { path: "/products" }, { path: "/careers/:jobId" }, { path: "/careers" }, { path: "/about-us" }, { path: "/features" }, { path: "/usecase/:usecaseId" } ];

const re = new RegExp('^\/(\\w)+\/:.*Id\/?$', 'i');

const selectedRoutes = ROUTES.filter((item) => {
  return !item.path.match(re)
});

console.log(selectedRoutes);

edited Dec 16, 2022 at 10:17

Nitheesh

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answered Dec 16, 2022 at 10:13

Rohìt Jíndal

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Comments

Nitheesh · Accepted Answer · 2022-12-16 10:18:13Z

0

How about using regular expressions (regexp)?

const ROUTES = [ { path: "/" }, { path: "/faqs" }, { path: "/contactus" }, { path: "/pricing" }, { path: "/products" }, { path: "/careers/:jobId" }, { path: "/careers" }, { path: "/about-us" }, { path: "/features" }, { path: "/usecase/:usecaseId" } ];

const re = new RegExp('/.*/:.*Id', 'i');

const selectedRoutes = ROUTES.map((item) => {
  if (item.path === "/")
    return "";
  else
    return item.path;
}).filter((item) => {
  return !item.match(re)
});

console.log(selectedRoutes);

edited Dec 16, 2022 at 10:18

Nitheesh

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answered Dec 13, 2022 at 10:39

berserck

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Comments

Nitheesh · Accepted Answer · 2022-12-16 10:18:33Z

0

const ROUTES = [ { path: "/" }, { path: "/faqs" }, { path: "/contactus" }, { path: "/pricing" }, { path: "/products" }, { path: "/careers/:jobId" }, { path: "/careers" }, { path: "/about-us" }, { path: "/features" }, { path: "/usecase/:usecaseId" } ];

const selectedRoutes = ROUTES.map( (item) => {
  if (item.path === "/")
    return "";
else
return item.path;
}).filter( (item) => { return !item.includes(":")}); 

console.log(selectedRoutes);

edited Dec 16, 2022 at 10:18

Nitheesh

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answered Dec 13, 2022 at 9:45

Miss Shrivastava

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