How I can scan my array within array if there is equal array element. I want to check if its true or false
// the array to be scan
const array = [
[0, 1, 2],
[3, 4, 5],
[6, 7, 8],
]
// the new array
const newArray = [0, 1, 2]
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Have you checked how-to-compare-arrays-in-javascript？flyingfox– flyingfox2022-11-25 06:35:22 +00:00Commented Nov 25, 2022 at 6:35
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not yet, but my problem is, the array is inside of array so what will I need to do to it in order to compare itKrune– Krune2022-11-25 06:40:03 +00:00Commented Nov 25, 2022 at 6:40
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4 Answers
Based on anwser from how-to-compare-arrays-in-javascript,you just need to iterate the first array and then compare them
const array = [
[0, 1, 2],
[3, 4, 5],
[6, 7, 8],
]
// the new array
const newArray1 = [0, 1, 2]
const newArray2 = [0, 1, 3]
const checkArray = (array1,array2) => {
for(let arr of array1){
if(arr.length === array2.length && arr.every((v,i) => v === array2[i])){
return true
}
}
return false
}
console.log(checkArray(array,newArray1))
console.log(checkArray(array,newArray2))
Comments
You can use every method to check all the items.
array.filter((arr)=>arr.every((item,index)=>newArray[index]===item))
1 Comment
adiga
Doesn't work when the
newArray has same elements at the index but has more elements: array = [[1]], newArray = [1,2,3]run a foreach or for loop with a combination of name.find(x => x.ref === value);
or use array.filter((arr)=>arr.every((item,index)=>newArray[index]===item))
1 Comment
adiga
Doesn't work when the
newArray has same elements at the index but has more elements: array = [[1]], newArray = [1,2,3]const array = [
[0, 1, 2],
[3, 4, 5],
[6, 7, 8],
];
const newArray = [0, 1, 2]
let isPresent = false;
for (let i = 0; i < array.length; i++) {
if (JSON.stringify(array[i]) == JSON.stringify(newArray)) {
isPresent = true
break
}
}
console.log(isPresent)After stringifying the array you are able to compare directly in js and If it matches I changed the boolean value to true.
In case you have any doubts feel free to comment.
