Async Javascript function is returning undefined in NodeJS

Question

I am trying to call a function which gets data from an API and after comaprison of received data with input it should return 0 or 1 which i may include in my code but the function is returning undefined. Can;t seem to get my head in the right place.


async function cloudVerify(y, x) {
  const url = `https://**myAPI**.execute-api.us-west-2.amazonaws.com/items/${y}`;
  console.log(url);
  await axios
    .get(url)
    .then((res) => {
      const headerDate =
        res.headers && res.headers.date ? res.headers.date : "no response date";
      console.log("Status Code:", res.status);
      console.log("Date in Response header:", headerDate);

      const receivedData = res.data;
      const receivedItem = receivedData.Item;
      // console.log(receivedItem);
      console.log(
        `Got user with id: ${receivedItem.id}, hash: ${receivedItem.hash}`
      );
      console.log(`received item hash is ${receivedItem.hash}`);
      console.log(`meta is : ${x}, hash: ${receivedItem.hash}`);
      return 1;
    })
    .catch((err) => {
      console.log("Error: ", err.message);
    });
}

I am returning 1 but instead it gives me undefined.

Can you show us the function where you are logging the result from function is ...? There is some kind of typo on your question preventing your code from displaying correctly. Maybe you could fix that also — Boguz
– Boguz, Commented Nov 9, 2022 at 8:31
Does this answer your question? Async/Await with Request-Promise returns Undefined — Shoejep
– Shoejep, Commented Nov 9, 2022 at 8:32

Daniel Karlsson · Accepted Answer · 2022-11-09 08:38:33Z

1

When you return 1 inside the "then" method you will not return it from the cloudVerify function. You need to type return before "await axios" as well.

answered Nov 9, 2022 at 8:38

Daniel Karlsson

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Comments

hernanl · Accepted Answer · 2022-11-09 08:44:15Z

0

I think it's a scoping issue. the "return 1" is returned by your call to axios within cloudVerify, it's not the return value of that function.

Also, you might be mixing async/await with .then() - you might be able to drop the async/await and simply return the call to axios. kind of like this:

callingAxios = () => {
  axios.get().then()
  return 1
}

cloudVerify = (url) => {
  return callingAxios(url)
}

answered Nov 9, 2022 at 8:44

hernanl

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