How to check if array contain duplicate object value? [duplicate]

Question

I need to find true of false if my array contain duplicate object value.

Suppose I have this array of objects

const array = [
    {
        id: "id1",
        quantity: 3,
        variation: "red",
        tax: 40
    },
    {
        id: "id1",
        quantity: 3,
        variation: "red",
        tax: 40
    },
    {
        id: "id2",
        quantity: 3,
        variation: "red",
        tax: 40
    }
]

Here I have to get true because here id1 come twice in this array. If This array contain unique id everywhere then it should return false. How can I do that. I am not getting proper solution.

Does it have to be only id or any property? Every other property is identical. — link2name
– link2name, Commented Oct 23, 2022 at 12:15
"I am not getting proper solution." is not really a clear question though. What are you stuck on? Do you know how to check values in an array? If not, you could start with a for loop. — Kokodoko
– Kokodoko, Commented Oct 23, 2022 at 12:18

Usitha Indeewara · Accepted Answer · 2022-10-23 12:26:43Z

0

You can use the following function:

function checkDuplicates(arr) {
    let result = false;
    let ids = [];

    for(let x = 0; x < arr.length; x++) {
        if(ids.includes(arr[x].id)) {
            result = true;
            break;
        } else {
            ids.push(arr[x].id);
        }
    }

    return result;
}

console.log(checkDuplicates(array))

Hope it helps.

edited Oct 23, 2022 at 12:26

answered Oct 23, 2022 at 12:20

Usitha Indeewara

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