remove duplicate from array of objects based on condition

Question

I have this array of objects I have tried to remove a duplicate from the array, but I can't remove it based on a condition this is the array

result = [
  { jobId: 2, requiredNumber: 2, acceptableRate: 80 },
  { jobId: 3, requiredNumber: 3, acceptableRate: 80 },
  { jobId: 4, requiredNumber: 1, acceptableRate: 80 },
  { jobId: 2, requiredNumber: 1, acceptableRate: 95 } 
]

what I have done is using the .filter() and the .findIndex() but I can't get my excepted output this is what I have done

var mm = result.filter(
  (value, index, self) =>
    index === self.findIndex((t) => t.jobId === value.jobId)
);
console.log(mm);

my output was

[
  { jobId: 2, requiredNumber: 2, acceptableRate: 80 },
  { jobId: 3, requiredNumber: 3, acceptableRate: 80 },
  { jobId: 4, requiredNumber: 1, acceptableRate: 80 }
]

expected output is based on my condition which can be based on higher acceptableRate or higher requiredNumber

[
  { jobId: 2, requiredNumber: 1, acceptableRate: 95 },
  { jobId: 3, requiredNumber: 3, acceptableRate: 80 },
  { jobId: 4, requiredNumber: 1, acceptableRate: 80 },
]

Define "duplicate", I don't understand your expected output. — Aymane Hrouch
– Aymane Hrouch, Commented Oct 8, 2022 at 23:29
From the above question it seems to remove duplicate JobID record which have lower acceptable rate in case of equal acceptable rate in jobID remove lower required number record. — Jitendra Pathak
– Jitendra Pathak, Commented Oct 8, 2022 at 23:35

Lukas249 · Accepted Answer · 2022-10-09 00:05:23Z

2

First sort the array by acceptableRate or if they are the same values by requiredNumber then find duplicates. This way.

result = [
    { jobId: 2, requiredNumber: 2, acceptableRate: 80 },
    { jobId: 3, requiredNumber: 3, acceptableRate: 80 },
    { jobId: 4, requiredNumber: 1, acceptableRate: 80 },
    { jobId: 2, requiredNumber: 1, acceptableRate: 95 },
];

 result.sort(function (a, b) {
     return b.acceptableRate - a.acceptableRate || b.requiredNumber - a.requiredNumber;
 });

var mm = result.filter(
    (value, index, self) =>
        index === self.findIndex((t) => t.jobId === value.jobId),
);

console.log(mm);

edited Oct 9, 2022 at 0:05

answered Oct 8, 2022 at 23:38

Lukas249

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Comments

Haim Abeles · Accepted Answer · 2022-10-08 23:49:42Z

0

The following code will filter the values for you if the jobId comes first according to acceptableRate, and if there are two identical values then it will filter according to requiredNumber

var mm = result.sort((a, b) => b.jobId < a.jobId ? true : b.jobId > a.jobId ? false : b.acceptableRate > a.acceptableRate ? true : b.acceptableRate < a.acceptableRate ? false : b.requiredNumber - a.requiredNumber);

answered Oct 8, 2022 at 23:49

Haim Abeles

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Comments

Alexey Zelenin · Accepted Answer · 2022-10-08 23:50:33Z

0

If I understood your question right, here might be the code. We filter out all the items if there's an item with same jobId and higher acceptableRate.

const result = [
  { jobId: 2, requiredNumber: 2, acceptableRate: 80 },
  { jobId: 3, requiredNumber: 3, acceptableRate: 80 },
  { jobId: 4, requiredNumber: 1, acceptableRate: 80 },
  { jobId: 2, requiredNumber: 1, acceptableRate: 95 } 
];

const finalResult = result.filter(x => 
    !result.find(r => 
        r.jobId === x.jobId && 
        r.acceptableRate > x.acceptableRate));
console.log(finalResult);

answered Oct 8, 2022 at 23:50

Alexey Zelenin

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