Parsing command line arguments in Python: getting a KeyError

Question

I am trying execute my Python script as:

python series.py supernatural 4 6

Supernatural : TV Series name 
4 : season number
6 : episode number

Now in my script I am using the above three arguments to fetch the title of the episode:

import tvrage.api
import sys

a =  sys.argv[1] 
b = sys.argv[2]
c =  sys.argv[3]

temp = tvrage.api.Show(a)
name  = temp.season(b).episode(c)  # Line:19
print ( name.title)

But I am getting this error:

File "series.py", line 19, in <module>:
  name = super.season(b).episode(c) 
File "C:\Python26\Lib\site-packages\tvrage\api.py", line 212, in season
  return self.episodes[n] KeyError: '4'

I am using Python 2.6.

actually the error is pointing to api i am using but if u want error is ` File "series.py", line 19, in <module> name = super.season(b).episode(c) File "C:\Python26\Lib\site-packages\tvrage\api.py", line 212, in season` return self.episodes[n] KeyError: '4' — RanRag
– RanRag, Commented Sep 13, 2011 at 0:19

agf · Accepted Answer · 2011-09-13 00:23:18Z

3

The Python TVRage API is expecting integers, not strings (which is what you get from argv):

name = temp.season(int(b)).episode(int(c))

will correct the error, if season 4 episode 6 exists.

You should take a look at the command line parsing modules that come with Python. For 3.2 / 2.7 or newer, use argparse. For older versions, use optparse. If you already know C's getopt, use getopt.

answered Sep 13, 2011 at 0:23

agf

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agf · Accepted Answer · 2011-09-13 01:20:12Z

3

A KeyError means you're trying to access an item in a dictionary that doesn't exist. This code will generate the error, because there's no 'three' key in the dictionary:

>>> d = dict(one=1, two=2)
>>> d
{'two': 2, 'one': 1}
>>> d['three']
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
KeyError: 'three'

See the Python Wiki entry on KeyErrors.

edited Sep 13, 2011 at 1:20

agf

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answered Sep 13, 2011 at 0:24

Seth

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1 Comment

agf Over a year ago

That's a fine description of a KeyError but doesn't answer the question -- it doesn't tell him why that key doesn't exist in the dictionary.

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