return the output value of a function that asks for an output variable

Question

Title is a bit messy, but i dont know how to simplify it. This is what i want to do:

nodeReceivedData[packetSize+1] = itoa(LoRa.packetRssi(), [output], 10);

itoa() always asks for a input variable, output variable and a size modifier. What I want to do, is to avoid having to make a temporary variable to then assign it's value to the actual variable I want that data to be. Is there something that can do this?

I also tried:

itoa(LoRa.packetRssi(), &nodeReceivedData[packetSize+1], 10);

but since nodeReceivedData is a byte type variable, itoa() won't accept it.

Extra info:

int LoRaClass::packetRssi()

byte nodeReceivedData[50]

What is itoa doing in C++ code? It's not even standard in C. What is the objective here? Why not convert to std::string? — tadman
– tadman, Commented Oct 1, 2022 at 23:38
itoa(LoRa.packetRssi(), (char*)&nodeReceivedData[packetSize+1], 10); — Igor Tandetnik
– Igor Tandetnik, Commented Oct 2, 2022 at 0:19

Pain67 · Accepted Answer · 2022-10-02 01:15:07Z

1

Since "itoa" expects the 2nd argument to be "char*" and 'nodeReceivedData' is byte (assuming it is just an "unsigned char"), you can just cast it to a char* and should work as expected:

itoa(LoRa.packetRssi(), (char*)&nodeReceivedData[packetSize+1], 10);

answered Oct 2, 2022 at 1:15

Pain67

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