yaml-cpp error while converting Node to a std::string

Question

I want to convert a Node object from yaml-cpp to a std::string. I keep getting an error that says it cannot find the right overloaded operator <<. Here's my code:

#include <iostream>
#include <string>
#include <yaml-cpp/yaml.h>

using namespace std;

int main(int argc, char* argv[]) {
    YAML::Node myNode;
    myNode["hello"] = "world";
    cout << myNode << endl; // That works but I want that not to stdout

    string myString = "";
    myNode >> myString; // Error at this line
    cout << myString << endl;
    return 0;
}

The error is

src/main.cpp:13:12: error: invalid operands to binary expression ('YAML::Node' and 'std::string' (aka 'basic_string<char, char_traits<char>, allocator<char>>')
[somefile] note: candidate function template not viable: no known conversion from 'YAML::Node' to 'std::byte' for 1st argument
  operator>> (byte  __lhs, _Integer __shift) noexcept
  ^
[A bunch of these 10+]

Using clang++ -std=c++20 -I./include -lyaml-cpp -o prog main.cpp

Please help me find out!

Does this node type have an operator>> that takes a string? — Nicol Bolas
– Nicol Bolas, Commented Sep 25, 2022 at 17:30

Sisyffe · Accepted Answer · 2022-09-25 17:44:04Z

1

Actually needed to create an stringstream and then convert it to an normal string:

#include <iostream>
#include <string>
#include <yaml-cpp/yaml.h>

using namespace std;

int main(int argc, char* argv[]) {
    YAML::Node myNode;
    myNode["hello"] = "world";

    stringstream myStringStream;
    myStringStream << myNode;
    string result = myStringStream.str();

    cout << result << end;
    return 0;
}

Output:

hello: world

answered Sep 25, 2022 at 17:44

Sisyffe

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1 Comment

Remy Lebeau Over a year ago

You should use std::ostringstream instead.

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