Filter duplicate records and push into array with additional condition using js

Question

I wan to filter the list of objects where city and state are not same, and then create a list of cities out of the filtered objects where temperature is less than 40. but condition is both sate and city should not be same

let arr = [
{
city:"chennai",
state: "tamilnadu",
temp: 44
},
 {
city:"coimbator",
state: "tamilnadu",
temp: 39
},
{
city:"mumbai",
state: "maharashtra",
temp: 32
},
{
city:"delhi",
state: "delhi",
temp: 24
},
{
city:"kolkata",
state: "west bengal",
temp: 28
}
];

Javascript code:

const uniqueStateCity = [];

const unique = arr.filter(element => {
const isDuplicate = uniqueStateCity.includes(element.city);
  
 if (!isDuplicate) {
  
  if(element.temp < 40)
  {
    uniqueStateCity.push(element.city );
    return true;
  
  }
}
  return false;
   
});

console.log(unique );

@pixlboy working but I am unable to check both state and city.. present code is filter only city.. but I want code in such a way it should filter state & city. — user_1234
– user_1234, Commented Sep 22, 2022 at 10:33
what is there are 2 cities in a same state with temperature less than 40 ? — pixlboy
– pixlboy, Commented Sep 22, 2022 at 10:37
you could have used a better input for your example that actually contains a duplicate — IT goldman
– IT goldman, Commented Sep 22, 2022 at 10:37
Its a poor example in code and question is not telling whether we should compare city and state in same object or with others. — pixlboy
– pixlboy, Commented Sep 22, 2022 at 10:38

score 2 · Accepted Answer · 2022-09-22 11:00:31Z

2

You should try this in your code!

just put condition in the result statement with arrow function and you are good to go.

    let arr = [
  {
    city: "chennai",
    state: "tamilnadu",
    temp: 44,
  },
  {
    city: "coimbator",
    state: "tamilnadu",
    temp: 39,
  },
  {
    city: "mumbai",
    state: "maharashtra",
    temp: 32,
  },
  {
    city: "delhi",
    state: "delhi",
    temp: 24,
  },
  {
    city: "kolkata",
    state: "west bengal",
    temp: 28,
  },
];

const result = arr.filter((data) => data.temp < 40 && data.state !== data.city);
const data = result.map((x) => x.city);
console.log(data);

edited Sep 22, 2022 at 11:00

answered Sep 22, 2022 at 10:35

user20052132

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8 Comments

MrCodingB Over a year ago

This doesn't check for uniqueness as OP originally implemented it.

user20052132 Over a year ago

Yeah, I agree but you can see I just used filter to print it while you do not need map function for it.

user_1234 Over a year ago

@KishanDobariya please check my updated question even check for state also different

user20052132 Over a year ago

Yeah, Let me take a look back on this and I will edit my answer. Thank you for response

pixlboy Over a year ago

OP wants full object in array and not just city names.

|

MrCodingB · Accepted Answer · 2022-09-22 16:36:37Z

This checks for uniqueness of city and state values and also handles your additional conditions. It will not add values which have the same city and the same state value as any other object in the array.

const arr = [
  {
    city: "chennai",
    state: "tamilnadu",
    temp: 44,
  },
  {
    city: "coimbator",
    state: "tamilnadu",
    temp: 39,
  },
  {
    city: "mumbai",
    state: "maharashtra",
    temp: 32,
  },
  {
    city: "mumbai",
    state: "maharashtra",
    temp: 32,
  },
  {
    city: "delhi",
    state: "delhi",
    temp: 24,
  },
  {
    city: "kolkata",
    state: "west bengal",
    temp: 28,
  }
];

const result = arr.reduce((all, cur) => { 
  if (
    all.findIndex((c) => c.city === cur.city && c.state === cur.state) < 0 &&
    cur.state !== cur.city && 
    cur.temp < 40
  ) {
    all.push(cur);
  }

  return all;
}, []);

console.log(result);

Monam Ben Gouta · Accepted Answer · 2022-09-22 11:52:04Z

1

let arr = [
  {
    city: "chennai",
    state: "tamilnadu",
    temp: 44,
  },
  {
    city: "coimbator",
    state: "tamilnadu",
    temp: 39,
  },
  {
    city: "mumbai",
    state: "maharashtra",
    temp: 32,
  },
  {
    city: "mumbai",
    state: "maharashtra",
    temp: 32,
  },
  {
    city: "delhi",
    state: "delhi",
    temp: 24,
  },
  {
    city: "kolkata",
    state: "west bengal",
    temp: 28,
  },
];
const result = [
...new Set(
arr.filter((data) => data.temp < 40 && data.state !== data.city).map((data) => data.city)
)
];
console.log(result);

answered Sep 22, 2022 at 11:52

Monam Ben Gouta

113 bronze badges

Comments

zlatanned · Accepted Answer · 2022-09-22 12:57:37Z

0

Since you want to filter out the objects having same names for city and state and with temperature greater than 40.

Also if your original arr has duplicate objects, and you want an array of unique objects. You can use:

const result = arr.filter(data => data.temp < 40 && data.state !== data.city);

for (let i = 0; i < result.length; ++i) {
    for (let j = 0; j < result.length; ++j) {
        if ( i !== j && 
             result[i].city === result[j].city && 
             result[i].state === result[j].state && 
             result[i].temp === result[j].temp
        ) {
            result.splice(j, 1);
        }
    }
}

edited Sep 22, 2022 at 12:57

answered Sep 22, 2022 at 12:29

zlatanned

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