I am trying to launch a python script from another python script in a new shell window. So far I'm unable to do it. Does anyone knows how can I accomplish this?
for example
import subprocess
process = subprocess.Popen('test.py', shell=True, stdout=subprocess.PIPE)
process.wait()
print (process.returncode)
when I'll run this script, it should launch 'test.py' in a new a new shell window.
I'm using linux, but it will be very helpful if you can provide solution for windows too.
Here's how you could do it on Debian-like systems:
import subprocess
import shlex
process = subprocess.Popen(
shlex.split("""x-terminal-emulator -e 'bash -c "test.py"'"""), stdout=subprocess.PIPE)
process.wait()
print (process.returncode)
Something like it should work for any *nix system.
Many thanks to eudoxos for pointing out x-terminal-emulator!
x-terminal-emulator is (at least on Debian and Ubutnu) symlink to the user-selected terminal, and should work always (unlike gnome-terminal)
x-terminal-emulator is set at the OS level, not on a per-user basis. I don't think it helps to replace gnome-terminal with x-terminal-emulator since, if x-terminal-emulator points to something other than gnome-terminal then the arguments -x bash -c "test.py" are likely to be invalid or nonsensical.xterm program, so using -e as the last option (with quoted command) should work just fine for any terminal emulator.Instead of launching a shell, launch a terminal running your script. On Linux, xterm -e test.py; the Windows equivalent would be cmd.exe test.py I believe (but I could be wrong).
