Script that execute C by Bash

Question

What should a script that compiles and executes a C program look like? By condition, the script must be run with the following flags: gcc -Wall -Werror -Wextra -o

In my understanding, when running the script, I have to enter the name of the program file

% gcc -Wall -Werror -Wextra "file_name".c -o "file_name"
% ./"file_name"

What you have is not unreasonable, but you probably should not execute the code unless it is built successfully. ie, gcc ... "$file".c && ./"$file". — William Pursell
– William Pursell, Commented Jun 29, 2022 at 16:11
There could be strong cybersecurity issues. You need to trust the human who gave you that C code. — Basile Starynkevitch
– Basile Starynkevitch, Commented Jun 29, 2022 at 16:16

Barmar · Accepted Answer · 2022-06-29 16:13:27Z

1

The script can take the name of the program as an argument, which you access using $1. Then substitute that for the file name in the commands.

#!/bin/sh

prog="$1"

if gcc -Wall -Werror -Wextra "$prog".c -o "$prog"
then "./$prog"
else
    echo "$prog.c did not compile successfully"
fi

answered Jun 29, 2022 at 16:13

Barmar

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3CEZVQ · Accepted Answer · 2022-06-29 16:29:03Z

0

#!/bin/sh

gcc -Wall -Werror -Wextra "$1".c -o "$1" && "./$1" || echo "Unable to compile and run $1"

Compile with gcc and run a program if it is successfully compiled, otherwise show the message to user.

Run the script like

script_name file_name

answered Jun 29, 2022 at 16:29

3CEZVQ

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