Javascript function with default argument and a multiple-argument [duplicate]

Let's say I have a function declaration like this:

function manyParams(a, b=1, ...n) { ... }

Now clearly I can call this function in such a way that I can provide a, b, and then any number of additional arguments under an array n.

Example:

function manyParams(a, b=1, ...n) {
    console.log(JSON.stringify(a));
    console.log(JSON.stringify(b));
    console.log(n.length);
}

If you call this function with the following arguments manyParams(1, 1, "John", "Stacy", "Mike", "Bob", "carly");, you get this output, which makes sense:

1
1
5

However, what if I want to use the default value in b, while still providing many arguments, how do I specify that "John" is the start of n? I would think I could do something like this: manyParams(a=1, n="John", "Stacy", "Mike", "Bob", "carly"); but that doesn't work. Running those arguments gives me the following output:

1
"John"
4