Python Error : json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

Question

When I run my Python file I get the following error:

config = open('config.json', 'r')
config_data = json.load(config_file)

This is my json file:

{
 "temp_unit": "celsius"
}

I get the following error:

Traceback (most recent call last):
  File "/home/paul/Documents/Nouvale/main.py", line 90, in <module>
    App.read_config()
  File "/home/paul/Documents/Nouvale/main.py", line 35, in read_config
    config_data = json.load(config_file)
  File "/usr/lib/python3.10/json/__init__.py", line 293, in load
    return loads(fp.read(),
  File "/usr/lib/python3.10/json/__init__.py", line 346, in loads
    return _default_decoder.decode(s)
  File "/usr/lib/python3.10/json/decoder.py", line 337, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "/usr/lib/python3.10/json/decoder.py", line 355, in raw_decode
    raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

Does anyone know how I can fix this? I am using Zorin 16.1 Pro, Python 3.8.10 & Pip 20.0.2.

Paul · Accepted Answer · 2022-06-13 22:39:55Z

1

Soloution

To fix the error I added an encoding parameter.

config = open('config.json', 'r', encoding='utf-8')
config_data = json.load(config)

edited Jun 13, 2022 at 22:39

answered Jun 11, 2022 at 11:52

Paul

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