Checking if the string is in proper format in Shell Scripting

Question

I am trying to check if the string is in format in shell script. below is the code i am trying and the output i want to get.

Format: <datatype>(length,length) | <datatype>(length,length)

I have multiple cases with this scenario, if both datatypes have () then it should show pass, else fail.

Eg. decimal(1,0)|number(11,0) this should pass but int|number(11,0) or decimal(1,0)|int should fail.

Code1:

INPUT='decimal(1,0)|number(11,0)'
sub="[A-Z][a-z]['!@#$ %^&*()_+'][0-9][|][A-Z][a-z]['!@#$ %^&*()_+'][0-9][|]"
if [ "$INPUT" == "$sub" ]; then
    echo "Passed"
else
    echo "No"
fi

Code 2:

INPUT='decimal(1,0)|number(11,0)'
sub="decimal"
if [ "$INPUT" == *"("*") |"*"("*") " ]; then
    echo "Passed"
else
    echo "No"
fi

Any help will be fine. Also note, I am very new to shell scripting.

You want =~, not ==, for a regular expression operation. = is a glob. And if you do want a glob, you can't quote the right-hand side -- it should be [[ $INPUT = $sub ]] -- note [[ instead of [; [ only supports exact comparisons (and only in [[ are unquoted expansions safe). — Charles Duffy
– Charles Duffy, Commented Apr 26, 2022 at 15:07
The above is only true in shells like bash with ksh extensions; /bin/sh doesn't support [[ at all, nor does it have any kind of built-in regex support, though you can evaluate globs there using case. — Charles Duffy
– Charles Duffy, Commented Apr 26, 2022 at 15:08
Thanks for the quick response and information . But i require the sub string which i can use in the if condition and add the other code i wan to impelement. — nishit dey
– nishit dey, Commented Apr 26, 2022 at 15:16
You can nest case inside of if. Baseline POSIX-standard /bin/sh simply doesn't support any substring operation without case; you need an extended shell (ksh, bash, zsh, etc) for that to be built-in. — Charles Duffy
– Charles Duffy, Commented Apr 26, 2022 at 16:31
Also, note that [ isn't guaranteed to support == at all. The only standard-defined string comparison operator is =. — Charles Duffy
– Charles Duffy, Commented Apr 26, 2022 at 16:35

LMC · Accepted Answer · 2022-05-14 16:04:49Z

2

+100

Reading both values into variables, first removing alpha characters and then checking variables are not empty

result='FAIL'
input='int|number(6,10)'

IFS="|" read val1 val2 <<<"$(tr -d '[:alpha:]' <<<"$input")"

if [ -n "$val1" ] && [ -n "$val2" ]; then
    result='PASS'
fi
echo "$result: val1='$val1' val2='$val2'"

Result:

FAIL: val1='' val2='(6,10)'

For input='decimal(8,9)|number(6,10)'

PASS: val1='(8,9)' val2='(6,10)'

edited May 14, 2022 at 16:04

answered May 14, 2022 at 0:12

LMC

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KamilCuk · Accepted Answer · 2022-05-13 12:26:07Z

2

That looks like just a simple regex to write.

INPUT='decimal(1,0)|number(11,0)'
if printf "%s" "$INPUT" | grep -qEx '[a-z]+\([0-9]+,[0-9]+\)(\|[a-z]+\([0-9]+,[0-9]+\))*'; then
    echo "Passed"
else
    echo "No"
fi

answered May 13, 2022 at 12:26

KamilCuk

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